Explanation:
The orbital radius of the Earth is 
The orbital radius of the Mercury is 
The orbital radius of the Pluto is 
We need to find the time required for light to travel from the Sun to each of the three planets.
(a) For Sun -Earth,
Kepler's third law :

M is mass of sun, 
So,

(b) For Sun -Mercury,

(c) For Sun-Pluto,

We are given that the wavelength ʎ is from 400 nm to 700
nm. The formula for this is:
d sin a =m * ʎ
where,
d = slit separation = 1 mm / 750 lines = 1/750
a = angle
m = 1
ʎ = 400 nm to 700 nm = 0.0004 mm to 0.0007 mm
Rewriting the formula in terms of angle a:
a = sin^-1 (m ʎ / d)
when ʎ = 0.0004 mm
a = sin^-1 (0.0004 / (1/750))
a = 17.46°
when ʎ = 0.0007 mm
a = sin^-1 (0.0007 / (1/750))
a = 31.67°
Hence the range of angles is from 17.46° to 31.67<span>°.</span>
Let the tension in the thread will be at angle theta
now by force balance in x and y directions we can say



now for the height of the kite we can use



<em>so it will be at height 32.23 m from ground</em>