Aluminum is the most similar
Answer:
Math expression: 
Explanation:
<u>Given:</u>
Energy produced per gram of gasoline = 45.0 kJ
Density of gasoline = 0.77 g/ml
Volume of gasoline = 5.2 L=5200 ml
<u>To determine:</u>
The amount of energy produced by burning 5.2 L gasoline
<u>Calculation set-up:</u>
1. Calculate the mass (m) of gasoline given the density (d) and volume (v)

2. Calculate the amount of energy produced

Answer:

Explanation:
Hello,
At first, the answer is wrong, consider the following procedure:
- the pKs, leads to a Ks of:


- now, stating the equilibrium for the calcium sulfate (whereas x is the change during the equilibrium):
![Ks=[Ca^{+2}]^{eq}[SO_{4}^{-2}]^{eq}\\Ks=[x]^{eq}[x]^{eq}\\Ks=x^{2}\\x=\sqrt{2.63x10^{-5}}\\x=5.13x10^{-3} M](https://tex.z-dn.net/?f=Ks%3D%5BCa%5E%7B%2B2%7D%5D%5E%7Beq%7D%5BSO_%7B4%7D%5E%7B-2%7D%5D%5E%7Beq%7D%5C%5CKs%3D%5Bx%5D%5E%7Beq%7D%5Bx%5D%5E%7Beq%7D%5C%5CKs%3Dx%5E%7B2%7D%5C%5Cx%3D%5Csqrt%7B2.63x10%5E%7B-5%7D%7D%5C%5Cx%3D5.13x10%5E%7B-3%7D%20M)
- x becomes the concentration of calcium ions and one of the contributions for the total concentration of sulfate ions, thus:
![[Ca^{+2}]^{eq}=5.13x10^{-3} M](https://tex.z-dn.net/?f=%5BCa%5E%7B%2B2%7D%5D%5E%7Beq%7D%3D5.13x10%5E%7B-3%7D%20M)
- finally, since the sodium sulfate is totally dissolved, we just simply add its concentration (equal to the sulfate ions yielded by itself) to the outgoing sulfate concentration from the calcium sulfate:
![[SO_4^{-2}]^{total}=5x10^{-3}M+5.13x10^{-3}M\\[SO_4^{-2}]^{total}=0.010 M](https://tex.z-dn.net/?f=%5BSO_4%5E%7B-2%7D%5D%5E%7Btotal%7D%3D5x10%5E%7B-3%7DM%2B5.13x10%5E%7B-3%7DM%5C%5C%5BSO_4%5E%7B-2%7D%5D%5E%7Btotal%7D%3D0.010%20M)
Bibliography:https://books.google.com.co/books?id=LQwyfFc3pXsC&lpg=PA243&ots=zIJN3nSFWE&dq=pKs%20chemistry&pg=PA244#v=onepage&q=pKs%20chemistry&f=false page 243
Best regards!
Answer:
It raises the boiling point and lowers the freezing point.
Explanation:
It is used as antifreeze in the cooling circuits of internal combustion engines, that is, it is used to reduce the melting point of the solution.
By adding ethylene glycol I'm not only bringing the melting point to -13°C, but the boiling point of ethylene glycol is 197°C.
since these substances not only lower the freezing point but also increase the boiling point, they are also called a colligative agent
I’m really sorry I need points I hope you find an answer