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Anna35 [415]
3 years ago
14

I answered a question correctly and someone deleted my answer without giving me any explanation. I don't know why someone would

do that but its really rude. Like someone is trying to help others and you are deleting their answers. What is this?? ​I am not going to answer any questions from now on.​
Chemistry
1 answer:
lina2011 [118]3 years ago
5 0

Answer:

Same, my answer got deleted. Its a troll on here who wants to screw around with people.

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laiz [17]
Aluminum is the most similar
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3 years ago
A gram of gasoline produces 45.0kJ of energy when burned. Gasoline has a density of 0.77/gmL. How would you calculate the amount
Ber [7]

Answer:

Math expression: =\frac{0.77\ g/ml*5200\ ml}{1\ g} *45.0\ kJ

Explanation:

<u>Given:</u>

Energy produced per gram of gasoline = 45.0 kJ

Density of gasoline = 0.77 g/ml

Volume of gasoline = 5.2  L=5200 ml

<u>To determine:</u>

The amount of energy produced by burning 5.2 L gasoline

<u>Calculation set-up:</u>

1. Calculate the mass (m) of gasoline given the density (d) and volume (v)

m = d*v\\\\m = 0.77 g/ml*5200 ml

2. Calculate the amount of energy produced

=\frac{0.77\ g/ml*5200\ ml}{1\ g} *45.0\ kJ=180180 kJ

7 0
3 years ago
You made up a saturated solution of calcium sulfate (CaSO4). The temperature is 25°C. You then add 5.00 × 10−3 M sodium sulfate
BARSIC [14]

Answer:

Ca^{+2}=5.13x10^{-3}M\\SO_4^{-2}=0.010 M

Explanation:

Hello,

At first, the answer is wrong, consider the following procedure:

- the pKs, leads to a Ks of:

pKs=-Log(Ks)

Ks=10^{-4.58}=2.63x10^{-5}

- now, stating the equilibrium for the calcium sulfate (whereas x is the change during the equilibrium):

Ks=[Ca^{+2}]^{eq}[SO_{4}^{-2}]^{eq}\\Ks=[x]^{eq}[x]^{eq}\\Ks=x^{2}\\x=\sqrt{2.63x10^{-5}}\\x=5.13x10^{-3} M

- x becomes the concentration of calcium ions and one of the contributions for the total concentration of sulfate ions, thus:

[Ca^{+2}]^{eq}=5.13x10^{-3} M

- finally, since the sodium sulfate is totally dissolved, we just simply add its concentration (equal to the sulfate ions yielded by itself) to the outgoing sulfate concentration from the calcium sulfate:

[SO_4^{-2}]^{total}=5x10^{-3}M+5.13x10^{-3}M\\[SO_4^{-2}]^{total}=0.010 M

Bibliography:https://books.google.com.co/books?id=LQwyfFc3pXsC&lpg=PA243&ots=zIJN3nSFWE&dq=pKs%20chemistry&pg=PA244#v=onepage&q=pKs%20chemistry&f=false page 243

Best regards!

7 0
3 years ago
Read 2 more answers
What does ethylene glycol do to the solution in a vehicle’s radiator? It raises the boiling point and lowers the freezing point.
zheka24 [161]

Answer:

It raises the boiling point and lowers the freezing point.

Explanation:

It is used as antifreeze in the cooling circuits of internal combustion engines, that is, it is used to reduce the melting point of the solution.

By adding ethylene glycol I'm not only bringing the melting point to -13°C, but the boiling point of ethylene glycol is 197°C.

since these substances not only lower the freezing point but also increase the boiling point, they are also called a colligative agent

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3 years ago
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At a certain concentration of N2 and H2, the initial rate of reaction is 5.0 x 105 M / s. What would the initial rate of the rea
Andreyy89
I’m really sorry I need points I hope you find an answer
6 0
3 years ago
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