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elena55 [62]
3 years ago
6

Which of the following situations has more kinetic energy than potential energy?

Physics
1 answer:
MrMuchimi3 years ago
3 0

Answer:

C. a rolling bowling ball

I just answered this question on my quiz.  

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The formation of atp as a result of the activity of the electron transport system is termed substrate-level phosphorylation is c
Zigmanuir [339]

Answer:

Oxidative phosphorylation

Explanation:

This takes place mostly in the organelle called the mitochondrion.

Oxidation of nutrients in cells by enzymes results in the release of the chemical energy present in the molecular energy.

The NADH and succinate products of the citric acid cycle are also oxidized. All this series of reactions takes place in the Electron transport system.The energy from the oxidation is used to produce adenosine triphosphate (ATP) hence the name oxidative phosphorylation.

4 0
3 years ago
A rifle with a weight of 40 N fires a 5.5-g bullet with a speed of 220 m/s.(a) Find the recoil speed of the rifle.
liubo4ka [24]

Answer:

0.2695/s

Explanation:

Using the formula for calculating impulse

Impulse = m(v-u) = Ft

M is the mass

v is the final velocity.

u is the initial velocity

F is the force

t is the time

Get the time;

t = m(v-u)/F

t = 0.0055(220)/40

t = 0.0275s

Get the speed of the rifle

v = u+gt.

v = 0+9.8(0.0275).

v = 0.2695m/s

Hence the speed of the rifle is 0.2695m/s

3 0
3 years ago
A particular car has a weight of 9500 N. What is the mass of the car? 9500 kg 95000 kg 950 kg 2160 kg
Ivenika [448]

950kg. It is W=mg. therefore, mass= W/g which is W/10

=9500/10

=950

8 0
3 years ago
1. Consider a 1000 kg car rounding a curve on a flat road of radius 50 m at a speed of
raketka [301]

Answer:

The car will make the turn perfectly

Explanation:

Given that the centripetal force= mv^2/r

M= mass of the car

v = speed of the car

r= radius

Hence;

F = 1000 × (14)^2/50

F= 3920 N

The frictional force = μmg

μ = coefficient of static friction

m= mass

g = acceleration due to gravity

Frictional force= 0.6 × 1000× 10

Frictional force = 6000 N

The car will not skid off the curve because the frictional force is greater than the centripetal force.

6 0
3 years ago
It is weigh-in time for the local under 85 kg rugby team. The bathroom scale used to assess eligibilty can be described by Hooke
Varvara68 [4.7K]
<span>k = 1.7 x 10^5 kg/s^2 Player mass = 69 kg Hooke's law states F = kX where F = Force k = spring constant X = deflection So let's solve for k, the substitute the known values and calculate. Don't forget the local gravitational acceleration. F = kX F/X = k 115 kg* 9.8 m/s^2 / 0.65 cm = 115 kg* 9.8 m/s^2 / 0.0065 m = 1127 kg*m/s^2 / 0.0065 m = 173384.6154 kg/s^2 Rounding to 2 significant figures gives 1.7 x 10^5 kg/s^2 Since Hooke's law is a linear relationship, we could either use the calculated value of the spring constant along with the local gravitational acceleration, or we can simply take advantage of the ratio. The ratio will be both easier and more accurate. So X/0.39 cm = 115 kg/0.65 cm X = 44.85 kg/0.65 X = 69 kg The player masses 69 kg.</span>
4 0
3 years ago
Read 2 more answers
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