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steposvetlana [31]
3 years ago
7

A 4.2-m-diameter merry-go-round is rotating freely with an angular velocity of 0.80 rad????s. Its total moment of inertia is 136

0 kg ???? m2. Four people standing on the ground, each of mass 65 kg, suddenly step onto the edge of the merry-go-round. (a) What is the angular velocity of the merry-go-round now? (b) What if the people were on it initially and then jumped off in a radial direction (relative to the merry-go-round)
Physics
1 answer:
Lina20 [59]3 years ago
5 0

Answer:

A) 0.44 rad/s

B) 3.091 rad/s

Explanation:

Initial angular momentum must be equal to final angular momentum.

W1 = 0.80 rad/s

I = 1360 kgm^2

Initial moment Iw = 0.8 x 1360 = 1088 rad-kg-m^2/s

For second case

I = (65 x 4)4.2 + 1360 = 2452 kg-m2-rad/s

New momentum = 2452 x W2

Where w2 = final angular momentum

= 2452W2

Equating both moment,

1088 = 2452W2

W2 = 0.44 rad/s0

If they were on it before,

Initial momentum

I = 1360 - (60 x 4)4.2

= 352 rad-kg-m^2/s

352W1 = 1088

W1 = 3.091 rad/s

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