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olya-2409 [2.1K]

3 years ago

5

In a darkened room, a burning candle is placed 1.84 m from white wall. A lens is placed between candle and wall at a location th

at causes a larger, inverted image to form on the wall. When the lens is moved 82.4 cm toward the wall, another image of the candle is formed. How far apart are the two object distances that produce these images? Answer in units of m

1 answer:

KATRIN_1 [288]3 years ago

7 0

Answer:

82.4 cm

Explanation:

The object and screen are kept fixed ie the distance between them is fixed and by displacing lens between them images are formed on the screen . In the first case let u be the object distance and v be the image distance

then ,

u + v = 184 cm

In the second case of image formation , v becomes u and u becomes v only then image formation in the second case is possible.

The difference between two object distance ie( v - u ) is the distance by which lens is moved so

v - u = 82.4 cm

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We can solve the problem by using Ohm's law, which states that an Ohmic conductor the following relationship holds:
$\Delta V = I R$
where
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In our problem, I=4.00 A and $R=330 \omega$ , so the potential difference is
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7 0

3 years ago

4) A football player starts at the 40-yard line, and runs to the 25-yard line in 2 seconds.

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Answer:

(a). Their speed during that run is 10 m/s.

(b). Their velocity is 6.86 m/s

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Explanation:

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Suppose, the distance between 40 yard line and 25 yard line is 20 yard.

(a). We need to calculate their speed during that run

Using formula of speed

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t = time

Put the value into the formula

$v=\dfrac{18.288}{2}$

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(b). We need to calculate their velocity

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Put the value into the formula

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Negative sign shows the direction of motion.

(c). If they kept running at that velocity for another 1.3 seconds,

We need to calculate the final position

Using formula of position

$d=vt$

Put the value into the formula

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8 0

3 years ago

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Answer:

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Explanation:

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$r = 12.0 \mu m$

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$V = \frac{4}{3}\pi (12\mu m)^3$

$V = 7.24 \times 10^{-15} m^3$

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so weight of the pollen is given as

$W = mg$

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$W = 7.1 \times 10^{-11}$

Now electric force on the pollen is given

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$\frac{F}{W} = \frac{6.65 \times 10^{-14}}{7.1 \times 10^{-11}}$

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7 0

2 years ago

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kupik [55]

Answer:

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3 years ago