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Goshia [24]
3 years ago
12

While moving a box 10.0 m across the floor, Sam pushes with a force of 150 N to the right. The force friction acting on the box

is 25.0 N to the left. What is the net work done on the box by these 2 forces
Physics
1 answer:
svet-max [94.6K]3 years ago
4 0

Answer:

Explanation:required formula is

W 1=F*S

W1=work done by Sam =?

F=force applied by sam=150N

S=displacement =10m

again

W2=F*S

W2=work done by friction =?

S=displacement =10m

F=friction =25N

W=W1-W2=net work done

please feel free to ask if you have any questions

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Work done is the distance a force acts over.

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5 0
3 years ago
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zaharov [31]

Answer:

(A) L = 115.3kgm²/s

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Explanation:

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7 0
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You throw a ball downward from a window at a speed of 2.0m/s. How far has it fallen in 3 seconds?
bekas [8.4K]
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3 0
3 years ago
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VikaD [51]
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-----------------------
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3 years ago
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