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Kruka [31]
3 years ago
5

Effects of the earths orbit around the sun

Physics
1 answer:
makvit [3.9K]3 years ago
7 0
<h3><u>Effects of the earths orbit around the sun:</u></h3>

The earth moves around the sun in an elliptical orbit, Johannes Kepler, a "German mathematician, and astronomer" described this elliptical orbit first. The orbit is close to being a circle but not a circle. Earth orbiting the sun mainly effects on seasons on earth.

Earth's four seasons are determined when Earth is tilted 23.4 degrees on the vertical axis, which is called as “axial tilt”. When a "southern hemisphere is tilted towards the sun", it experiences summer and northern hemisphere experiences winter, exactly opposite happens when northern hemisphere tilts towards Sun and this climate change goes on in all countries.

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The complete combustion of a small wooden match produces approximately 512 cal of heat. How many kilojoules are produced? Expres
k0ka [10]

We have to covert 512 cal of heat in kilo joules.

As, 1 cal = 0.004184 kJ = 4.184 joules.

Therefore,

512 \ cal = 512 \times 4.184 \ J = 2142.208 \ J \\\\\ =  2.142 \times 10 ^3 J = 2.142 \ kJ

Thus, combustion of a small wooden match produces approximately ( in kilo joules ) is 2.142 kJ .

5 0
3 years ago
A car traveling at 50 km/h hits a bridge abutment. A passenger in the car moves forward a distance of 61 cm (with respect to the
Karolina [17]

Answer:

6957.04N

Explanation:

Using

vf2=vi2+2ad

But vf = 0 .

So convert 50km/hr to m/s, and you need to convert 61 cmto m

(50km/hr)*(1hr/3600s)*(1000m/km) = 13.9m/s

61cm * (1m/100cm) = .61m

So n

0 = (13.9m/s)^2 + 2a(.61m)

a = 158.11m/s^2

So

using F = ma

F = 44kg(158.11m/s^2) = 6957.04N

3 0
3 years ago
Read 2 more answers
What is the speed of sound in air at 40°C?
Blababa [14]
343 meters per second Is the answer
4 0
3 years ago
Read 2 more answers
Cam Newton can sprint 40 meters in 5.79 seconds! How fast can he run?<br> Show your work
Setler79 [48]

Speed=Distance/Time

Distance=40m,time=5.79seconds

S=40/5.79

=6.908m/s

6 0
2 years ago
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The melting point of potassium thiocyanate determined by a student in the laboratory turned out to be 174.5 oC. The accepted val
yaroslaw [1]

Answer:

0.75%

Explanation:

Measured value of melting point of potassium thiocyanate = 174.5 °C

Actual value of melting point of potassium thiocyanate = 173.2 °C

<em>Error in the reading = |Experimental value - Theoretical value|</em>

<em>= |174.5 - 173.2|</em>

<em>= |1.3|</em>

<em>Percentage error = (Error / Theoretical value) × 100</em>

<em>= (1.3 / 173.2)×100</em>

<em>= 0.75 %</em>

∴ Percentage error in the reading is 0.75%

4 0
2 years ago
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