Answer:
The kinetic energy of the system after the collision is 9 J.
Explanation:
It is given that,
Mass of object 1, m₁ = 3 kg
Speed of object 1, v₁ = 2 m/s
Mass of object 2, m₂ = 6 kg
Speed of object 2, v₂ = -1 m/s (it is moving in left)
Since, the collision is elastic. The kinetic energy of the system before the collision is equal to the kinetic energy of the system after the collision. Let it is E. So,

E = 9 J
So, the kinetic energy of the system after the collision is 9 J. Hence, this is the required solution.
Answer:
38 m
Explanation:
Number of turns=N=100
Magnetic field=B=0.50 T
Frequency of the generator=f=60 Hz
Rms value of emf=
We have to find the length of the wire from which the coil is made.
Peak value of emf=
Length of wire=
Substitute the values
Length of wire=
Length of wire=38 m
Hence, the length of wire from which the coil is made=38 m
<span>Nuclei of u-238 atoms are </span><span>unstable and spontaneously emit alpha particles.</span>
Force = (mass) x (acceleration) Newton's second law of motion.
Force = (2 kg) x (3 m/s²) = 6 newtons.