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Lorico [155]
3 years ago
8

Which is evidence that a convergent boundary once existed

Physics
1 answer:
Vladimir79 [104]3 years ago
8 0

Volcanic islands, Mountain ranges

Explanation:

A convergent margin is plate boundary in which plates comes together. There are different types of interactions that occurs around a place where plate converges.

  • An ocean-continent convergence creates a subduction zone in which the denser oceanic plate sinks beneath the less dense continental crust.
  • As the oceanic plate begins to subside, it can melt and form chains of volcanic island within the riding continents.
  • Also, where two plates of equal densities converge, none of them subsides and this leads to upbuilding.
  • The product can be seen as extensive mountain ranges on earth like the Andes and Himalayas.

Learn more:

Descending lithosphere brainly.com/question/9582362

#learnwithBrainly

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Andrei [34K]
2 is c
3 is a 
4 is b
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3 0
3 years ago
The left end of a long glass rod 8.00 cm in diameter, with an index of refraction 1.60, is ground to a concave hemispherical sur
sp2606 [1]

Answer:

a) q = -9.23 cm, b)  h’= 0.577 mm , c) image is right and virtual

Explanation:

This is an optical exercise, where the constructor equation should be used

        1 / f = 1 / p + 1 / q

Where f is the focal length, p the distance to the object and q the distance to the image

A) The cocal distance is framed with the relationship

       1 / f = (n₂-1) (1 /R₁ -1 /R₂)

In this case we have a rod whereby the first surface is flat R1 =∞ and the second surface R2 = -4 cm, the sign is for being concave

       1 / f = (1.60 -1) (1 /∞ - 1 / (-4))

       1 / f = 0.6 / 4 = 0.15

        f = 6.67 cm

We have the distance to the object p = 24.0 cm, let's calculate

       1 / q = 1 / f - 1 / p

       1 / q = 1 / 6.67 - 1/24

       1 / q = 0.15 - 0.04167 = 0.10833

       q = -9.23 cm

distance to the negative image is before the lens

B) the magnification of the lenses is given by

       M = h ’/ h = - q / p

        h’= - q / p h

        h’= - (-9.23) / 24.0 0.150

        h’= 0.05759 cm

        h’= 0.577 mm

C) the object is after the focal length, therefore, the image is right and virtual

6 0
3 years ago
A vector A⃗ has a magnitude of 40.0 m and points in a direction 20.0∘ below the positive x axis. A second vector, B⃗, has a magn
jolli1 [7]

The magnitude of the vector C is 96.32m

<h3>How to solve for the magnitude of vector c</h3>

Ax = AcosθA

= 40 cOS 20

= 37.59

Ay = AsinθA

-40sin20

= -13.68

Bx = B cos θ B

= 75Cos50

= 48.21

By = BsinθB

= 75sin50

= 57.45

Cx = AX + Bx

= 37.59 + 48.21

= 85.8

Cy = Ay + By

= -13.65 + 57.45

= 43.77

The magnitude is solved by

|c| = \sqrt{Cx^{2}+Cy^{2}  }

= √85.8² + 43.77²

= 96.32m

The magnitude of the vector c is 96.32m

Read more on the magnitude of a vector here:

brainly.com/question/3184914

#SPJ1

6 0
2 years ago
The electron has the positron as its antiparticle.<br><br> A True<br> B False
Sphinxa [80]
The answer would be true
8 0
3 years ago
Read 2 more answers
I will mark brainliest if right :)
kozerog [31]

Answer:

Explanation:

compressions and rarefactions

4 0
3 years ago
Read 2 more answers
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