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IRINA_888 [86]
3 years ago
5

A millionairess was told in 1992 that she had exactly 15 years to live. However, if she immediately takes off, travels away from

the Earth at 0.8 c and then returns at the same speed, the last New Year's Day the doctors expect her to celebrate is:
Physics
1 answer:
mamaluj [8]3 years ago
7 0

Answer:

The expected year is 2017.

Explanation:

Total years that the millionaire to live = 15 years

Travel away from the earth at  = 0.8 c

This is a time dilation problem so if she travels at 0.8 c then her time will pass at slower. Below is the following calculation:

T = \frac{T_o}{ \sqrt{1-\frac{V^2}{c^2}}} \\T = \frac{15}{ \sqrt{1-\frac{0.8^2}{c^2}}} \\T = 25 years

Thus the doctors are expecting to celebrate in the year, 1992 + 25 = 2017

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A car, initially traveling 28.0ft/s, steadily speeds up to 50.0ft/s in 7.40s. Determine all unknowns and answer the following qu
nataly862011 [7]

Explanation:

Given:

v_0 = 28.0\:\text{ft/s}

v = 50.0\:\text{ft/s}

t = 7.40\:\text{s}

First, we calculate the acceleration of the car during this time:

v = v_0 + at \Rightarrow a = \dfrac{v - v_0}{t}

Plugging in the given values, we get

a = \dfrac{50.0\:\text{ft/s} - 28.0\:\text{ft/s}}{7.40\:\text{s}} = 2.97\:\text{ft/s}^2

Now that we have the value for the acceleration, we can solve for the distance traveled during the time t:

x = v_0t + \frac{1}{2}at^2

\:\:\:\:=(28.0\:\text{ft/s})(7.40\:\text{s})

\:\:\:\:\:\:\:\:\:\:\:\:+ \frac{1}{2}(2.97\:\text{ft/s}^2)(7.40\:\text{s})^2

\:\:\:\:= 289\:\text{ft}

7 0
3 years ago
Please help thank you! Quarter ends tomorrow
dimaraw [331]
1.) is gonna be one or two 2.) one
5 0
3 years ago
A man wears convex lens glasses of focal length 30cm in order to correct his eyes defect. Instead of the optimum 25cm, his dista
omeli [17]

Answer:

14 cm

Explanation:

F = (frac{uv}{u – v})

F = +ve

v = -ve

30 = (frac {25 {times} (-v)}{25 – (-v)})

v = (frac {25 {times} (-v)}{25+v})

v = 14cm

(Note that either negative or positive values go to show the positioning and hence, they are not a strong necessity in your final answer.)

So happy that i could help you!

Now this question could turn out to be easy for you!!

7 0
2 years ago
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defon

Answer:

DveC başarılar yardı olduysam sevinirim

6 0
3 years ago
A violin string is 45.0 cm long and has a mass of 0.242 g. When tightened on the neck of the violin, the distance between the pi
stiks02 [169]

Answer:

The tension is 75.22 Newtons

Explanation:

The velocity of a wave on a rope is:

v=\sqrt{\frac{TL}{M}} (1)

With T the tension, L the length of the string and M its mass.

Another more general expression for the velocity of a wave is the product of the wavelength (λ) and the frequency (f) of the wave:

v= \lambda f (2)

We can equate expression (1) and (2):

\sqrt{\frac{TL}{M}}=\lambda f

Solving for T

T= \frac{M(\lambda f)^2}{L} (3)

For this expression we already know M, f, and L. And indirectly we already know λ too. On a string fixed at its extremes we have standing waves ant the equation of the wavelength in function the number of the harmonic N_{harmonic} is:

\lambda_{harmonic}=\frac{2l}{N_{harmonic}}

It's is important to note that in our case L the length of the string is different from l the distance between the pin and fret to produce a Concert A, so for the first harmonic:

\lambda_{1}=\frac{2(0.425m)}{1}=0.85 m

We can now find T on (3) using all the values we have:

T= \frac{2.42\times10^{-3}(0.85* 440)^2}{0.45}

T=75.22 N

3 0
3 years ago
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