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VARVARA [1.3K]
3 years ago
12

A custodian pushes a 119 kg box across a level floor. The box moves at a constant velocity. The custodian pushes horizontally on

the box with a force of 724 Newtons, what must be the friction force experienced by the box in Newtons?
Physics
1 answer:
bonufazy [111]3 years ago
8 0

The friction force experienced by the box in Newtons is 724N

The frictional force is the force that opposes the moving force acting on a body on a horizontal plane.

  • For a static body, the acceleration will be zero,

According to Newton's second law of motion:

  • ∑Fx = ma
  • +Fm - Ff = ma

Given the following paramters

  • Moving force Fm = 724N
  • acceleration a = 0m/s²
  • mass m = 119 kg

Substitute the given parameters into the formula to get the frictional force:

724 - Ff = 119(0)

724 - Ff = 0

Ff = 0 + 724

Ff = 724N

Hence the friction force experienced by the box in Newtons is 724N

Learn more here: brainly.com/question/8859573

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If an X-ray tube is operating at a current of 30.0 mA:a) How many electrons are striking the target per second? b) If the potent
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Answer:

Explanation:

A. Q= It

30E-3A=q

Ne = q

30E-3/1.6*10-19= N

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The star Antares has an apparent magnitude of 1.0, whereas the star Procyon has an apparent magnitude of 0.4. Which star appears
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Answer:

Procyon appears brighter in the sky

Explanation:

Apparent magnitude of star Antares = 1.0

Apparent magnitude of star Procyon = 0.4

Pogson's Ratio

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where, m is the apparent magnitude

B = Brightness of star or flux coming towards us (W/m²)

∴Larger magnitudes correspond to fainter stars so here 1>0.4 which means Antares appears dimmer and Procyon appears brighter.

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3 years ago
A calorimeter has a heat capacity of 1265 J/oC. A reaction causes the temperature of the calorimeter to change from 22.34oC to 2
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<h2>Heat released in this process is 3516.7 J</h2>

Explanation:

A calorimeter has a heat capacity of 1265 J/°C

Heat capacity of calorimeter = 1265 J/°C

A reaction causes the temperature of the calorimeter to change from 22.34°C to 25.12°C

Change in temperature = 25.12 - 22.34 = 2.78°C

Heat released = Heat capacity of calorimeter x Change in temperature

Heat released = 1265 x 2.78 = 3516.7 J

Heat released in this process is 3516.7 J

5 0
4 years ago
Read 2 more answers
An electric motor has a rating of 4.0 × 10^2 watts.
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P_{ot}= \frac{P}{\Delta t} \\ \Delta t = \frac{P\Delta S}{P_{ot}}
 
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\Delta t = \frac{P\Delta S}{P_{ot}} \\ \Delta t = \frac{50*9.8*8}{4*10^2} \\ \boxed {\Delta t =9.8s}

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