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serious [3.7K]
3 years ago
8

A single sports fan is capable of yelling at an intensity level of 80 dB from a given distance. If 10,000 similar fans were all

yelling from the same distance, which of the following would be closest to the observed intensity level?
A. 84 dB
B. 120 dB
C. 160 dB
D. 320 dB
Physics
2 answers:
riadik2000 [5.3K]3 years ago
4 0

Answer: option "A" is correct

Explanation: the closet to understand the intensity level will be from 80db (decibels) upwards. So option a which is 84db is the answer. Thank you.

LenaWriter [7]3 years ago
3 0

Answer:

= 120dB

Explanation:

The Intensity level

L = 10 Log \frac{I_1}{I_0} for sigle fan

so,

I_1 = 10^8I_0 single fan intensity

Now intensity for 10000 fan

= 10^4 \times I_1 \\= 10^4 \times 10^8\\= 10^1^2I_0

Intensity level

L = 10log\frac{I_1}{I_0}

L = 10log \frac{10^1^2I_0}{I_0}

L = 120dB

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amid [387]

Answer:

(a) the final velocity of the cart is 0.857 m/s

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(c) the fraction of the initial energy lost is 0.71

Explanation:

Given;

mass of the package, m₁ = 10 kg

mass of the cart, m₂ = 25 kg

initial velocity of the package, u₁ = 3 m/s

initial velocity of the cart, u₂ = 0

let the final velocity of the cart = v

(a) Apply the principle of conservation of linear momentum to determine common final velocity for ineleastic collision;

m₁u₁  + m₂u₂ = v(m₁  +  m₂)

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30  = 35v

v = 30 / 35

v = 0.857 m/s

(b) the impulse experienced by the package;

The impulse = change in momentum of the package

J = ΔP = m₁v - m₁u₁

J = m₁(v - u₁)

J = 10(0.857 - 3)

J = -21.43 kg.m/s

the magnitude of the impulse experienced by the package = 21.43 kg.m/s

(c)

the initial kinetic energy of the package is calculated as;

K.E_i = \frac{1}{2} mu_1^2\\\\K.E_i = \frac{1}{2} \times 10 \times (3)^2\\\\K.E_i = 45 \ J\\\\

the final kinetic energy of the package;

K.E_f = \frac{1}{2} (m_1 + m_2)v^2\\\\K.E_f = \frac{1}{2} \times (10 + 25) \times 0.857^2\\\\K.E_f = 12.85 \ J

the fraction of the initial energy lost;

= \frac{\Delta K.E}{K.E_i} = \frac{45 -12.85}{45} = 0.71

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A car travels at a speed of 40 m/s for 29.0 s;<br>what is the distance traveled by the car?
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Answer: 1160 m

Explanation:

Speed = distance / time. Plug in 40 m/s for speed and 29 s for time in order to get the distance, 1160 m.

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suppose that you look into a photometer's eyepiece and the fluorescent disks appear to be equal in intensity. If the distance be
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I=1/(d*d)

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The use of calculations involves differentiation and integration. Integration enables evaluation of the expression of acceleration of speed and expression of movement at a distance. Similarly, differentiation allows us to evaluate expression of speed position and expression speed to acceleration.

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