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serious [3.7K]
3 years ago
8

A single sports fan is capable of yelling at an intensity level of 80 dB from a given distance. If 10,000 similar fans were all

yelling from the same distance, which of the following would be closest to the observed intensity level?
A. 84 dB
B. 120 dB
C. 160 dB
D. 320 dB
Physics
2 answers:
riadik2000 [5.3K]3 years ago
4 0

Answer: option "A" is correct

Explanation: the closet to understand the intensity level will be from 80db (decibels) upwards. So option a which is 84db is the answer. Thank you.

LenaWriter [7]3 years ago
3 0

Answer:

= 120dB

Explanation:

The Intensity level

L = 10 Log \frac{I_1}{I_0} for sigle fan

so,

I_1 = 10^8I_0 single fan intensity

Now intensity for 10000 fan

= 10^4 \times I_1 \\= 10^4 \times 10^8\\= 10^1^2I_0

Intensity level

L = 10log\frac{I_1}{I_0}

L = 10log \frac{10^1^2I_0}{I_0}

L = 120dB

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3 years ago
slader A transcontinental flight of 4890 km is scheduled to take 40 min longer westward than eastward. The airspeed of the airpl
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Answer:

v_{s}=65.2km/h

Explanation:

Given data

Flight distance S=4890 km

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To find

Speed of jet stream

Solution

When moving in the same direction as the jet stream time taken as t₁=d/(v+vs),v is velocity of plane and vs is velocity of plane

While moving in opposite direction t₂=d/(v+vs)

So

t_{2}-t_{1}=\frac{d}{(v-v_{s}) } - \frac{d}{(v+v_{s}) }\\t_{2}-t_{1}=\frac{d(v+v_{s})-d(v-v_{s})}{(v-v_{s})(v+v_{s})} \\t_{2}-t_{1}=\frac{2dv_{s}}{(v)^{2} -(v_{s})^{2} }\\0.666667h=\frac{2(4890km)v_{s}}{(980km/h)^{2} -(v_{s})^{2} }\\0.666667((980km/h)^{2} -(v_{s})^{2})=9780v_{s}\\640267-0.666667(v_{s})^{2}-9780v_{s}=0\\0.666667(v_{s})^{2}+9780v_{s}-640267=0

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