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iogann1982 [59]
2 years ago
8

A constant horizontal force F is applied to a 5 kg box on a frictionless horizontal surface. The box starts from rest and moves

12 meters in 5 seconds.
a) what is the magnitude of the force F?
b) If the force is withdrawn at the end of the 5 seconds, how far does the box move in the next 5 seconds?
Physics
1 answer:
sergejj [24]2 years ago
7 0
65(58)+85)6463(9786+)9_43=
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The difference between a law and a theory is the diffrence between what and why . Explain
siniylev [52]

Answer:

A law is defined as a description or a statement given after an observed phenomenon. A theory is a simplification of certain observational data as to how and why it happened.

Explanation:

I hope this helped solve your question.

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The production of carbon dioxide might be an indicator of what process
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A rock on the moon has a mass of 17kg, what is the mass if this same rock on earth?
NISA [10]

Mass is an intrinsic property of the rock.  The mass doesn't care where it is, and it makes no difference where the rock happens to be at the moment ... its mass doesn't change.

17kg of mass is 17kg .  If it's 17kg on the moon, it's <em>17kg</em> on Earth.

6 0
3 years ago
1. If the angle of the ramp were increased from 30˙ to 45˙, how would this change the weight of the box? Explain.
yawa3891 [41]

When the angle of the ramp increases, the weight of the box acting perpendicular to the ramp decreases.

<h3>Normal reaction of the box</h3>

The normal reaction of the box is due to weight of the box acting perpendicular to the ramp.

Fn = Wcosθ

<h3>when the angle of the ramp = 30⁰</h3>

Fn = Wcos(30)

Fn = 0.866W

<h3>when the angle of the ramp = 45⁰</h3>

Fn = W x cos(45)

Fn = 0.7071W

Thus, when the angle of the ramp increases, the weight of the box acting perpendicular to the ramp decreases.

Learn more about normal reaction here: brainly.com/question/18292235

#SPJ1

4 0
2 years ago
Work functions of tungsten and sodium are 4.4 eV and 2.3 eV respectively. If threshold
KonstantinChe [14]

Answer:

(d) 2840 A

Explanation:

Threshold frequency can be be calculated using expresion below

(λ)= hc/ Φ

(λ) sodium/ (λ)tungsten = Φtungsten/ Φsodium

But (λ) sodium is given as 5460 A,

Φsodium = 2.3 eV

Φtungsten= 4.4 eV

If we substitute the values we can find

(λ)tungsten.

(λ)tungsten= [(λ) sodium × Φsodium]/ Φtungsten

=( 5460× 2.3)/4.4

= 2854A

Hence, threshold wavelength of tungsten is 2854A

5 0
3 years ago
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