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Natali5045456 [20]
3 years ago
12

The specific heat of aluminum is 0.0215 cal/g°c. if a 4.55 g sample of aluminum absorbs 2.55 cal of energy, by how much will the

temperature of the sample change?
Physics
1 answer:
lakkis [162]3 years ago
8 0

The formula we will use on this one is:

E = m C ΔT

where,

E = energy

m = mass of sample

C = specific heat

ΔT = change in temperature

 

Calculating for ΔT:

ΔT = E / m C

ΔT = 2.55 cal / (4.55 g * 0.0215 cal/g°C)

ΔT = 0.098 °C

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In a physics lab, light with a wavelength of 570 travels in air from a laser to a photocell in a time of 16.5 . When a slab of g
aliina [53]

Answer:

Wavelength is calculated as 213.9 nm

Solution:

As per the question:

Wavelength of light = 570 nm

Time, t = 16.5 ns

Thickness of glass slab, d = 0.865 ns

Time taken to travel from laser to the photocell, t' = 21.3

Speed of light in vacuum, c = 3\times 10^{8}\ m/s

Now,

To calculate the wavelength of light inside the glass:

After the insertion of the glass slab into the beam, the extra time taken by light to cover a thickness t = 0.865 m is:

t' - t = 21.3 - 16.5 = 4.8 ns

Thus

\frac{d}{\frac{c}{n}} - \frac{d}{v} = 4.8\times 10^{- 9}

\frac{0.8656}{\frac{c}{n}} - \frac{0.865}{v} = 4.8\times 10^{- 9}

where

n = refractive index of the medium

v = speed of light in medium

\frac{0.8656}{\frac{c}{n}} - \frac{0.865}{v} = 4.8\times 10^{- 9}

n = \frac{4.8\times 10^{- 9}\times 3.00\times 10^{8}}{0.865} + 1

n = 2.66

Now,

The wavelength in the glass:

\lambda' = \frac{\lambda }{n}

\lambda' = \frac{570}{2.66} = 213.9\ nm

5 0
4 years ago
Please helo me to 1st question<br>​
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Explanation:

6 min in seconds:

6×60

<h2><u>360</u><u> </u><u>s</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u>s</u><u> </u></h2><h2 /><h2 />

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3 years ago
Describe what a reactant is
ohaa [14]

Answer:

the element that takes part in a chemical reactions

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except decomposition reactions

4 0
3 years ago
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Electromagnetic Induction states that moving a magnet through a loop of wire creates which of the following?
alukav5142 [94]
I am pretty sure that electromagnetic Induction states that moving a magnet through a loop of wire creates B. magnetic field. I consider this option to be correct because according to lenz's law <span>conductor  moves through loop and to be more exact in this case through a magnetic field. I hope it help!</span>
5 0
3 years ago
In one hour, coal supplies 500 000 J of energy. The energy amounts to 380 000 J. How much useful energy is produced in one hour?
Debora [2.8K]

Answer:

120,000J

Corrected question;

In one hour, coal supplies 500 000 J of energy. The wasted energy amounts to 380 000 J. How much useful energy is produced in one hour?

Explanation:

Given;

Total energy Et = 500,000 J

Wasted Energy Ew = 380,000J

The amount useful energy is the amount of energy that is available for supply.

This can be derived by subtracting the wasted energy from the total energy.

Useful energy = Total Energy - wasted energy

Eu = Et - Ew

Substituting the given values;

Eu = 500,000J - 380,000

Eu = 120,000 J

The amount of useful energy produced in one hour is 120,000 J

5 0
3 years ago
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