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rewona [7]
2 years ago
7

7. A block of copper of unknown mass has an initial temperature of 65.4oC. The copper is immersed in a beaker containing 95.7g o

f water at 22.7oC. When the two substances reach thermal equilibrium, the final temperature is 24.2oC. What is the mass of the copper block?
Physics
1 answer:
dolphi86 [110]2 years ago
5 0

Answer:

37.34372 kg

Explanation:

m = Mass

\Delta T = Change in temperature

1 denotes water

2 denotes copper

c = Heat capacity

Heat is given by

Q=mc\Delta T

In this case the heat transfer will be equal

m_1c_1\Delta T_1=m_2c_2\Delta T_2\\\Rightarrow m_2=\frac{m_1c_1\Delta T_1}{c_2\Delta T_2}\\\Rightarrow m_2=\frac{95.7\times 4.18(24.2-22.7)}{0.39(65.4-24.2)}\\\Rightarrow m_2=37.34372\ kg

Mass of copper block is 37.34372 kg

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KengaRu [80]

Answer:

the length of the wire is 134.62 m.

Explanation:

Given;

resistivity of the copper wire, ρ = 2.6 x 10⁻⁸ Ωm

cross-sectional area of the wire, A  = 35 x 10⁻⁴ cm² = ( 35 x 10⁻⁴) x 10⁻⁴ m²

resistance of the wire, R = 10Ω

The length of the wire is calculated as follows;

R = \frac{\rho L}{A} \\\\L = \frac{RA}{\rho} \\\\L= \frac{10 \times (35\times 10^{-4}) \times 10^{-4}}{2.6 \times 10^{-8}} \\\\L = 134.62 \ m

Therefore, the length of the wire is 134.62 m.

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2 years ago
If C moves to position 5 (60 meters), what is its average velocity during these 5 seconds?
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Velocity:

60 meters/ 5 seconds= 12 meters/second

Velocity=12meters/second

(60 meters divided by 5 seconds equals 12 meters per second)

Hope this helps!

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3 years ago
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Answer:

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2 years ago
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Please help if you have the time
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We know, length of segment wave is half the wavelength .

Let, wavelength of wave is \lambda.

So, length of segment will be \dfrac{\lambda}{2} .

Now, it is given that the string vibrates in four segments.

So,

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Snell's law describes the relationship between the angles of incidence and refraction.
n1*sin(theta1) = n2*sin(theta2)
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