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timama [110]
2 years ago
9

Can someone please answer this, ill give you brainliest and your getting 100 points.

Physics
2 answers:
Tanya [424]2 years ago
7 0

Answer:

Social cost is the answer

:D let's hope that helped

Explanation:

dsp732 years ago
5 0
It’s c hopefully that helps
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A Blu-ray disc is approximately 11 centimeters in diameter. The drive motor of a Blu-ray player is able to rotate up to 10,000 r
stepladder [879]

Answer:

the maximum angular speed (in radians per second) of a Blu-ray disc as it rotates is 57.6 m/s

Explanation:

Given information:

diameter of the disc, d  = 11 cm, r = 5.5 cm = 0.055 m

angular speed ω = 10000 rev/min = (10000 rev/min)(2π rad/rev)(1/60 min/s)

                             = 1000π/3 rad/s

to calculate the maximum angular speed we can use the following formula

ω = v/r

v = ωr

  = (1000π/3)(0.055)

  = 57.6 m/s

8 0
2 years ago
A velocity vs time graph what is the acceleration of the object
tigry1 [53]

Answer:

If the object is moving with an acceleration of +4 m/s/s (i.e., changing its velocity by 4 m/s per second), then the slope of the line will be +4 m/s/s.

Explanation:

7 0
2 years ago
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Charging a balloon by rubbing it on wool is an example of
SVETLANKA909090 [29]
Electronic friction ^.^
3 0
3 years ago
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Help help help please , i will give brainliest
finlep [7]

Answer:

I believe the answer for #1 is D and the answer for #2 is B

Explanation:

I hope this is correct and helps

6 0
3 years ago
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A jogger runs at a constant rate of 10.0 m every 2.0 seconds. The jogger starts at the origin and runs in the positive direction
Elis [28]

Answer:

(a) 25 m

(b) 75 m

Explanation:

Given that the jogger runs at a constant rate of 10.0 m every 2.0 seconds.

So, the speed of the jogger,

v=\frac{10}{2}=5m/s\;\cdots(i)

Let d be the distance covered by him in time, t s.

As distance=(speed) x (time)

So, d=vt

From equation (i)

\Rightarrow d=5t\;\cdots(ii)

As the jogger starts from origin, so, the distance, d, also represents the position of the jogger at the time t s.

The position-time graph has been shown.

(a) From equation (ii), for t=5.0 s

d=5\times 5=25 m

So, the jogger is at a distance of 25 m from the origin.

(b) Similarly, for t=15.0 s

d=5\times 15=75 m

So, the jogger is at a distance of 75 m from the origin.

8 0
2 years ago
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