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3 years ago

9

Can someone please answer this, ill give you brainliest and your getting 100 points.

2 answers:

Tanya [424]3 years ago

7 0

Answer:

Social cost is the answer

:D let's hope that helped

Explanation:

dsp733 years ago

5 0

It’s c hopefully that helps

You might be interested in

1. What is true about elements

yaroslaw [1]

W is the noble gas having atomic number 10 and configuration (2,8)
x, y and z are the s block elements. They have 2,2 and 1 electrons in their outermost shell respectively.
Atomic size decreases across the period and increases down the group. Element z is having more atomic size.

Hope it helps you!!!!

7 0

3 years ago

The Global Positioning System (GPS) is a constellation of about 24 artificial satellites. The GPS satellites are uniformly distr

Liono4ka [1.6K]

Answer:

b) 3.72m/s²

c) 9.33*10^5

d) 9.33*10^5

e) 11.85 hrs

Explanation:

a) to confirm that gEarth is about 98 m/s².

Let's use the formula:

$gEarth= \frac{G*M}{R^2}$

$= \frac{6.67*10^-^1^1*5.972*10^2^4}{(6378*10^3)^2}$

= 9.78 m/s²

=> 9.8m/s²

b) Given:

$m = 6.417*10^2^3$

r = 2106 miles

$g_Mars = \frac{G*M}{R^2}$

$= \frac{6.67*10^-^1^1*6.417*10^2^3}{(2106*1.61*10^3)^2}$

=3.72 m/s²

c) we use:

$F = \frac{G*M*m}{R^2}$

$=\frac{6.67*10^-^1^1*5.972*10^2^4*1630*10^3}{((20000+6378)*10^3)^2}$

$= 9.33*10^5 N$

d) Let's take the force of gravitybon earth due to satellite as our answer in (c) because the Earth's gravitational force on a GPS satellite and the force of gravity on a GPS satellite on earth are equal and opposite (two mutual forces).

$F = 9.33*10^5 N$

e) In a circular motion,

Gravitional force = Centripetal force.

$\frac{GM*m}{R^2}=\frac{m*v^2}{R}$

$\frac{GM}{R}= v^2$

Solving for v, we have

$v= \sqrt{\frac{6*67*10^-^1^1*5.972*10^2^4}{(20000+6278)*10^3}}$

v = 3886m/s

Therefore,

v = 2πR/T

$3886 = \frac{2*pi*(20000+6378)*10^3}{T}$

Solving for T, we have:

T = 42650seconds

Convert T to hours

T = 42650/60*60

T = 11.86hrs

6 0

4 years ago

What is the minimum tangential velocity a space station would need to simulate earth gravity if the radius is 50 meters ?

Aneli [31]

Explanation:

angular velocity is given by

$w = \sqrt{ \frac{g}{r} }$

$w = \sqrt{ \frac{9.8}{25} }$

w = 0.626

now tangential velocity is

V = rw

= 25 x 0.626

= 15.65 m/s

5 0

3 years ago

Explain Using the equation for translational kinetic energy, show why a car moving at 40 m/s has four times the translational ki

djverab [1.8K]

Answer:

Explanation:

Equation for translational kinetic energy = 1/2 m V² where m is mass and V is velocity .

In first case let mass of car be m

Translational kinetic energy = 1/2 m x 40² = 800 m .

In the second case ,

Translational kinetic energy = 1/2 m x 20² = 200 m

So , in former case kinetic energy of car is 4 times that of second case.

7 0

3 years ago

An object moves from position +34m to the position -15m in 15 seconds. What is the total displacement? What is the total velocit

Alexandra [31]

1) Displacement: -49 m, in the negative direction

Explanation:

The displacement of an object is a vector, whose magnitude is given by the difference between the final point of the motion and the starting point:

$d=p_f -p_i$

In this problem, the starting point is +34 m, while the final position is -15 m; therefore, the displacement is:

$d=-15 m- (+34 m)=-49 m$

and the direction is negative, in according to the negative sign.

2) Velocity: -3.27 m/s

Explanation:

Velocity is equal to the ratio between the displacement and the time taken:

$v=\frac{d}{t}$

in this problem, we have:

d = -49 m is the displacement

t = 15 s is the time

therefore, the velocity is

$v=\frac{-49 m}{15 s}=-3.27 m/s$

and the direction is negative.

8 0

3 years ago