If a particle undergoes simple harmonic motion with an amplitude of 0.21 meters, this means that the maximum displacement of the particle from its resting position is 0.21. For one period, it traveled from its starting position which is twice the amplitude and then back to its original position which is another distance that is twice the amplitude as well. Therefore, the total distance it traveled is 2*amplitude + 2*amplitude = 2*0.21 + 2*0.21 = 0.42 + 0.42 = 0.84 meters.
Answer:
The magnification is 133X
Explanation:
For a refractor telescope using convex lenses, the overall magnification os calculated as by dividing the focal length of the objective by that of the eyepiece.
So:
Care must be taken with the units, in this case they are in meters and centimeters, they should be converted into the same unit before calculating:
Copper is the higher concentrated metal in this case.
Scissors and a pen that is the answer
