Es frecuente que en las instalaciones eléctricas domésticas se utilice alambre de cobre de 2.05 mm de diámetro. Determine la res
1 answer:
Answer:
The resistance is 0.124 ohm.
Explanation:
It is common for domestic electrical installations to use copper wire with a diameter of 2.05 mm. Determine the resistance of such a wire with a length of 24.0 m.
diameter, d = 2.05 mm
radius, r = 1.025 mm
Length, L = 24 m
resistivity of copper = 1.7 x 10^-8 ohm m
Let the resistance is R.
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Answer:
Let's begin by explaining that the <u>electromagnetic spectrum</u> is the set of electromagnetic radiations distributed in their different frequencies or wavelengths. So, if we go from the smallest wavelengths known up to now (because according to physics the electromagnetic spectrum is infinite and continuous) to the longest, the electromagnetic spectrum covers the following radiations:
Gamma rays, X-rays, ultraviolet, visible light, infrared, radio waves and microwaves:
-Gamma rays: With a wavelength in the order of , is a type of ionizing radiation capable of penetrating matter quite deeply and is able to cause serious damage to the nucleus of the cells.
-X rays: With a wavelength between and
. It is invisible to the human eye, capable of crossing opaque bodies and is also an ionizing radiation.
-Ultraviolet light (UV): Whose wavelength is approximately between 100 nm and 380 nm; is a type of electromagnetic radiation that is not visible to the human eye.
-Visible light: This part of the spectrum is located between ultraviolet light and infrared light (400 nm - 800 nm). It should be noted, the fact the only part of the whole electromagnetic spectrum is visible to humans is because the receptors in our eyes are only sensitive to these wavelengths.
-Infrared: This type of radiation is not visible to the human eye, since its wavelengths are outside the visible spectrum (between 700 nm and 1 mm).
These waves can be divided into:
- Near infrared or long wave infrared: it is the least sensitive to color and is easily absorbed by water.
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Answer:
compared to the incident angle, the refracted angle is 45.56⁰
Explanation:
From Snell's law;
n₁sin(I) = n₂sin(r)
Where;
n₁ is the refractive index of light in medium 1 = 1.2
n₂ is the refractive index of light in medium 2 = 1.4
I is the incident angle
r is the refractive angle
I = 56.439⁰
Applying snell's law
Therefore, compared to the incident angle, the refracted angle is 45.56⁰