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Answer: 160.40 g Fe2O3 are needed.

Explanation:

Balanced equation: 2 Al + Fe2O3 —> Al2O3 + 2Fe

54.2 g Al * 1 mol Al / 26.98 g Al * 1 mol Fe2O3 / 2 mol Al * 159.69 g Fe2O3 / 1 mol = 160.40 g Fe2O3 are needed.

3 0

3 years ago

Part

Zielflug [23.3K]

NaOH (aq) + HCl(aq) => NaCl(aq)+ H2O(l)

Na+(aq)+ OH - (aq) + H +(aq) +Cl - (aq) + Cl- (aq)
=> Na+(aq) + Cl - (aq) + H2O(l)
H+(aq) + OH-(aq) => H2O(l)

6 0

3 years ago

Find the density of a block with a length of 8.0 cm, a width of

seraphim [82]

Answer:

<h3>Density = 0.5 g/cm³</h3>

Explanation:

Density of a substance can be found by using the formula

$Density = \frac{mass}{volume}$

From the question

mass = 32g

To find the density we must first find the volume of the block

From the question the block is a cuboid

Volume of cuboid = length × width × height

length = 8 cm

width = 4 cm

height = 2 cm

Volume of block = 8 × 4 × 2 = 64 cm³

Substitute the values into the above formula and solve for the density

That's....

$Density = \frac{32}{64} \\ = \frac{1}{2}$

We have the final answer as

Density = 0.5 g/cm³

The block will float because it's density is less than the density of water which is

1 g/cm³

Hope this helps you

6 0

3 years ago

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