Balanced Half reactions are:
At anode 2
==> Cl₂+ 
+ H₂O ==> 
+ 2
+
At Cathode: 2 + ==> H₂
Since the question states that you are using an aqueous solution of MnCl₂, so ions will have present are, H₂O, , 
and
Now at Anode reaction will occur as given:
2 ==> Cl₂+ + H₂O ==> + 2 + (will occur)
At Cathode:
2 + ==> H₂ (will occur)
At Cathode:
+ ==> Mn (This reaction will not occur)
The deposition of solid Mn will not occur because in aqueous solution, will be reduced before .
The reduction potentials for is zero whereas reduction potential for is - 1.18V.
The reduction potential of a species is its tendency to gain electrons and get reduced. It is measured in millivolts or volts. Larger positive values of reduction potential are indicative of a greater tendency to get reduced.
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There are three elements hydrogen, chlorine, and oxygen
Answer : The volume given to the patient should be, 85.5 mL
Explanation :
As we are given that the suspension contains 10g/15mL.
Now we have to determine the volume should be given to the patient.
As, 10 grams of lactulose syrup needed 15 mL volume of solution
So, 57 grams of lactulose syrup needed 
volume of solution
Thus, the volume given to the patient should be, 85.5 mL
Explanation:
it reacts with acid .......
Answer:
Imole/C=129 Directions Show All Of Your Work For Each Of The Following Problems. 1.
Explanation:
