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2 years ago

12

i'm begging ya'll i posted this about 3 times already and i'm really stuck. can someone please give me the answers to the cart?

i will give all my points and a brainliest.

1 answer:

Vedmedyk [2.9K]2 years ago

4 0

Answer:

just put the molecules and atoms where they belong

Explanation:

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A soccer ball is kicked with an initial horizontal velocity of 12 m/s and an initial vertical velocity of 19 m/s. 1 what is the

alex41 [277]

22.4722050542442 maybe I am not completely sure

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3 years ago

Physics help, thank you guys so much!

katrin2010 [14]

Answer:

Δt = 5.85 s

Explanation:

For this exercise let's use Faraday's Law

emf = $- \frac{d \phi}{dt}$ - d fi / dt

$\phi$ = B. A

\phi = B A cos θ

The bold are vectors. It indicates that the area of the body is A = 0.046 m², the magnetic field B = 1.4 T, also iindicate that the normal to the area is parallel to the field, therefore the angle θ = 0 and cos 0 =1.

suppose a linear change of the magnetic field

emf = - A $\frac{B_f - B_o}{ \Delta t}$

Dt = - A $\frac{B_f - B_o}{emf}$

the final field before a fault is zero

let's calculate

Δt = - 0.046 (0- 1.4) / 0.011

Δt = 5.85 s

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3 years ago

An observer notes that the pitch of a sound is becoming progressively higher.the observer can conclude that the sound is moving

Dahasolnce [82]

The observer can conclude that the sound is moving away from them and that its speed is increasing.

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3 years ago

PLEASE HELP :) THANK YOU Geologic processes change Earth's surface on varying scales of space and time. They range from rapid to

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Answer:

Human change the surface by mining it, falting it for land, we remove tree,plants, soil,mud, to build space for buidlings, farms, and etc hopes this help

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2 years ago

A ball is projected with an initial velocity of 40 meter per second and reached maximum height of 160 meters calculate tge angle

Andru [333]

There's a problem with the question as given. Even with a maximum projection angle of <em>θ</em> = 90°, the initial velocity is not large enough to get the ball up in the air 160 m. With angle 90°, the ball's height <em>y</em> at time <em>t</em> would be

<em>y</em> = (40 m/s) <em>t</em> - 1/2 <em>g t</em> ²

Set <em>y</em> = 160 m, and you'll find that there is no (real) solution for<em> t</em>, so the ball never attains the given maximum height.

From another perspective: recall that

<em>v </em>² - <em>v</em>₀² = 2<em>a </em>∆<em>y</em>

where

• <em>v</em>₀ = initial velocity

• <em>v</em> = final velocity

• <em>a</em> = acceleration

• ∆<em>y</em> = displacement

At its maximum height, the ball has zero vertical velocity, and ∆<em>y</em> = maximum height = 160 m. The ball is in free fall once it's launched, so <em>a</em> = -<em>g</em>.

So we have

0² - (40 m/s)² = -2<em>g </em>(160 m)

but this reduces to

(40 m/s)² = 2 (9.8 m/s²) (160 m)

1600 m²/s² ≠ 3136 m²/s²

7 0

3 years ago