We can first calculate the net force using the given information.
By Newton's second law, F(net) = ma:
F(net) = 25 * 4.3 = 107.5
We can now calculate the frictional force, f, which is working against the applied force, F(app) (this is why the net force is a bit lower):
f = F(net) - F(app) = 150 - 107.5 = 42.5 N
Now we can calculate the coefficient of friction, u, using the normal force, F(N):
f = uF(n) --> u = f/F(N)
u = 42.5/[25(9.8)]
u = 0.17
I think the answer its false i dont know how to explain that but it is false that what my teacher told me
For this case we have that the final speed is given by:
Where,
a: acceleration
vo: initial speed
t: time
Clearing the time we have:
Substituting values we have:
it takes 4.375 s for the car to stop
The sequence of energy transformations from the moment the ball is dropped to the moment the board is bent to its maximum extent and the ball is at rest is as follows:
1. The ball has potential energy (gravitational potential energy) from being held above the board.
2. As the ball is dropped, it gains kinetic energy as it accelerates to the ground.
3. When the ball hits the board, the kinetic energy is converted into elastic potential energy as the board bends.
4. As the board continues to bend, the elastic potential energy is converted into thermal energy.
5. Finally, when the board reaches its maximum extent, the ball is at rest and its kinetic energy has been completely converted into thermal energy.
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The car's average acceleration would be 1.25m/s^2 or 1.25meters/second/second. That looks to be the fourth one you've listed.