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vesna_86 [32]
3 years ago
9

Where are tidal generators located?

Chemistry
2 answers:
Sergio [31]3 years ago
8 0
A. in the ocean in the deep water because they can't swim
Sunny_sXe [5.5K]3 years ago
4 0
D , is the correct answer 
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I am a main group or representative element. I am located in
lesya692 [45]

Answer:

tantalum

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3 years ago
_______________ galaxies range in shape from almost perfect spheres to flattened globes with the light brightest in the center a
Mademuasel [1]
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6 0
4 years ago
Read 2 more answers
If i have 340mL of a 1.5 M NaBr solution, What will the concentration be for 1000mL?
Gekata [30.6K]

Answer:

0.51M

Explanation:

Given parameters:

Initial volume of NaBr = 340mL

Initial molarity  = 1.5M

Final volume  = 1000mL

Unknown:

Final molarity = ?

Solution;

This is a dilution problem whereas the concentration of a compound changes from one to another.

In this kind of problem, we must establish that the number of moles still remains the same.

    number of moles initially before diluting = number of moles after dilution

Number of moles  = Molarity x volume

Let us find the number of moles;

          Number of moles  = initial volume x initial molarity

Convert mL to dm³;

                  1000mL  = 1dm³

                     340mL gives \frac{340}{1000}   = 0.34dm³

Number of moles  = initial volume x initial molarity  = 0.34 x 1.5 = 0.51moles

Now to find the new molarity/concentration;

               Final molarity  = \frac{number of moles}{Volume}    = \frac{0.51}{1}    = 0.51M

We can see a massive drop in molarity this is due to dilution of the initial concentration.

6 0
3 years ago
You are in charge of inflating balloons for a parade. When you inflate the balloons in the morning, It will be 15 degrees Celsiu
tatiyna

Answer:

so you answer would be B

Explanation:

well what you would do is add 15+25=40  and what they are asking is whay are the degrees in the balloon so you would have B as your answer

hoped i helped have a great weekend

8 0
3 years ago
Cci(4) will be soluble in
Romashka-Z-Leto [24]
LIKE DISSOLVES LIKE. Since Ccl4 is non-polar, it'll be soluble in any non-polar solvent. Hope this helps you!
8 0
3 years ago
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