Answer:
43.2 moles of carbon dioxide are required and 421g of glucose could be produced
Explanation:
Based on the reaction:
6CO2 + 6H2O → C6H12O6 + 6O2
1 mole of glucose, C6H12O6, requires 6 moles of carbon dioxide. 7.2moles of glucose requires:
7.2mol C6H12O6 * (6mol CO2 / 1mol C6H12O6) =
<h3>43.2 moles of carbon dioxide are required</h3><h3 />
618g of CO2 -Molar mass: 44.01g/mol- are:
618g * (1mol / 44.01g) = 14.04moles CO2
Moles C6H12O6:
14.04moles CO2 * (1mol C6H12O6 / 6mol CO2) = 2.34moles C6H12O6
Mass glucose -Molar mass: 180.156g/mol-
2.34moles C6H12O6 * (180.156g / mol) =
<h3>421g of glucose could be produced</h3>
Answer:
D . oxidation and reduction oxidation
Answer:
The equation for Kinetic Energy is: KE = 1/2 mv2. Kinetic energy has a direct relationship with mass, meaning that as mass increases so does the Kinetic Energy of an object. The same is true of velocity. However, mass and velocity are indirectly related.
Answer: How does cellar respiration the law of converter of mass and the law of conversion of energy?
Explanation: Conservation of mass is the first law of thermodynamics. This states that energy is conserved in all processes, since it cannot be created nor destroyed. This applies to photosynthesis and cellular respiration.
Answer:
<h2>2.44 L</h2>
Explanation:
The volume can be used by using the formula for Boyle's law which is
where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
Since we're finding the final volume
We have
We have the final answer as
<h3>2.44 L</h3>
Hope this helps you
