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3 years ago

Explain the difference between contact and non-contact forces. Give an example of each

Physics

2 answers:

Sergio [31]3 years ago

8 0

Hi there

pushing on something that pushes back = action and reaction.

Gravity is non contact. Action at a distance. Hence stones wil fall if dropped.

Hoped I Helped

Amiraneli [1.4K]3 years ago

7 0

pushing on something that pushes back = action and reaction.

Gravity is non contact. Action at a distance. Hence stones wil fall if dropped.

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A pendulum with a mass of 1 kg and a spring-oscillator with the same mass of 1 kg are both oscillating with a period of 0.5 seco

maria [59]

Answer:

Explanation:

Period of the pendulum will not change as the period is not a function of mass

T = 2π√(L/g)

Period of the spring oscillator will increase with larger mass because period is a function of mass.

T = 2π/ω = 2π/√(k/m) = 2π√(m/k)

7 0

3 years ago

Consider a taut inextensible string. You shake the end of the string with some frequency, causing a wave to travel down the stri

masha68 [24]

Answer:

Part 1:

Option B is correct (It will remain unchanged).

Part 2:

Option C is correct (It will increase by a factor of √ 2)

Part 3:

Option E is correct (It will be half as fast/long.)

Part 4:

Option C is correct (It will increase by a factor of √ 2.)

Explanation:

Formula we are going to use:

V=f*λ

Where:

V is the speed of Sound

f is the frequency of wave

λ is the wavelength.

The speed of wave , tension and linear density have following relation:

$V=\sqrt{F/\rho}$

Where:

V is the speed of Sound (Initial)

F is the tension in string (Initial)

$\rho$ is the linear density of string (Constant)

Terms:

V' is the new speed

f' is the new frequency

λ' is the wavelength

Solution:

Part 1:

From $V=\sqrt{F/\rho}$ :

Speed of Sound is independent of the frequency of shaking so speed well remain unchanged.

Option B is correct (It will remain unchanged)

Part 2:

If F'=2F then

$V=\sqrt{F/\rho}$

$V'=\sqrt{F'/\rho}\\V'=\sqrt{2F/\rho}\\V'= \sqrt{2} * \sqrt{F/\rho}\\V'=\sqrt{2}V$

Option C is correct (It will increase by a factor of √ 2)

Part 3:

Formula we are going to use:

V=f*λ

Given f'=2f,

Even though frequency is doubled we will keep velocities same. V=V' in order to find the changing wavelength.

V'=f'*λ'

f*λ=f'*λ'

f*λ=2f*λ'

Solving above Equation:

λ'=λ/2

Option E is correct (It will be half as fast/long.)

Part 4:

T'=2T means $V'=\sqrt{2}V$ (From Part 1)

f'=f

Now:

V'=f'*λ'

$\sqrt{2}f*\lambda=f'*\lambda '\\\sqrt{2}f*\lambda=f*\lambda '\\ \lambda '=\sqrt{2}*\lambda$

Option C is correct (It will increase by a factor of √ 2.)

5 0

3 years ago

Overload refers to: A. Performing a weight-lifting exercise with the resistance (load) held overhead B. Using a demand (load) ab

andrey2020 [161]

Answer:

E. All of the answers are correct

Explanation:

Overload principle in fitness training is associated with a gradual development of an athlete's abilities by progressively increasing the athlete's load and training.

In order to do this, the athlete's limit must be surpassed albeit gradually at first then picked up later over time.

6 0

3 years ago

During a spring tide, what is arrangement of the moon, the sun and the earth?.

Solnce55 [7]

Explanation:

Spring tides generally occur twice a month—during new and full moons, when the Earth, Sun, and Moon line up in a row. In this arrangement, the gravities of the Sun and Moon work together and have the strongest pull on Earth. This produces the largest difference between high and low tide.

Spring Tides

During full moon or new moon phases, the gravitational forces of the Sun and Moon are maximized, producing very large ranges of tidal highs and lows called spring tides

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3 years ago

Why do you think more people give importance to their body than their mind?

tekilochka [14]

Answer:

More people give more importance to their body because they want to be liked and fit in. They would rather fail in school and mess up their education to show off their body to be one of those cool kids in school.

Explanation:

7 0

3 years ago