Using Kepler's 3rd law which is: T² = 4π²r³ / GM
Solved for r :
r = [GMT² / 4π²]⅓
Where G is the universal gravitational constant,M is the mass of the sun,T is the asteroid's period in seconds, andr is the radius of the orbit.
Change 5.00 years to seconds :
5.00years = 5.00years(365days/year)(24.0hours/day)(6... = 1.58 x 10^8s
The radius of the orbit then is computed:
r = [(6.67 x 10^-11N∙m²/kg²)(1.99 x 10^30kg)(1.58 x 10^8s)² / 4π²]⅓ = 4.38 x 10^11m
Answer:
117.83° F
Explanation:
Using Newton's Law of Cooling which can be expressed as:
The differential equation can be computed as:
where;
At the initial condition, T(0)= 350
replacing 
= 280 into (1)
Hence, the differential equation becomes:
when;
time (t) = 1 hour
T(1) = 250
Since;
k = -0.4418
Therefore;
T(t) = 70 + 280e^{(-0.4418)}t
After 4 hours, the temperature is:
T(t) = 70 + 280e^{(-0.4418)}4
T(4) = 117.83° F
Explanation:
Mg-2+C+4>Mg2C.
Here you divide the four by the two and transfer the two toMg. In reactions like this oxidation numbers are exchanged.
Sound travels 1,480 meters per second, which is about 4.3 times as fast as air. Sound travels much slowly in air. This has to do with the frequency, intensity and amplitude of waves, which are affected differently in water and air.
