The car's average <em>speed</em> is 97 km/hr.
Then for calculation purposes, we can assume that it covers 97 km in the
first hour, 97 km in the second hour, 97 km in the third hour, and 97 km in
the fourth hour.
All together, the car covers (97 x 4) = <em>388 km</em> of distance.
We don't know the car's velocity, because we have no information about the
<em>direction</em> it moved at any time during the four hours. So we have no way to
calculate how far it was from the starting point at the end of the fourth hour.
For all we can tell, if the direction (and therefore the velocity) varied just right,
the car could have ended up exactly where it started.
Answer:
Distance covered to top of the hill was : 1.755 km
Explanation:
Initial velocity = 35 km/hr
Acceleration = 2.0 km/hr²
Time taken to accelerate = 3 minutes = 3/60 hours = 1/20 hours
Formula for acceleration : a = Δv /t
v-u/t ---where u is initial velocity , v is final velocity and t is time taken for acceleration
v- 35 / 0.05 = 2
v = 35.10 km/h
Formula for distance is product of speed and time
Distance covered = 35.10 * 0.05 = 1.755 km
Answer:
Clockwise
Explanation:
All of the planets rotate the same way around the sun.
The solution for the problem is:
Constant speed means Fnet = 0.
Let m = mass of wood block and Θ = angle of ramp; then if µk = 0.35 …
The computation would be:
Fnet = 0 = mg (sin Θ) - (µk) (mg) (cos Θ)
mg (sin Θ) = µk (mg) (cos Θ)
µk = tan Θ
Θ = arctan(µk)
= arctan (0.35)
≈ 19.3°
