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Lelu [443]
3 years ago
11

A regulatory sign may be used to

Physics
1 answer:
charle [14.2K]3 years ago
4 0

Answer:

a. give limitations for using a particular lane of traffic

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A potential difference exists between the inner and outer surfaces of the membrane of a cell. The inner surface is negative rela
kifflom [539]

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Explanation:

Given

Work required W=1.35\times 10^{-20}\ J

Work done to eject the sodium ion from interior of the cell is given by the product of charge and Potential difference between inner and outer surface of the cell.

W=q\times V

Charge on sodium ion q=1.6\times 10^{19}\ C

V=\frac{W}{q}

V=\frac{1.35\times 10^{-20}}{1.6\times 10^{19}}

V=0.0718\ V            

8 0
3 years ago
Number 25 and 26 please!!!
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6 0
4 years ago
In the image below, astronauts detect approaching space junk and become
Wewaii [24]

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A

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3 years ago
What is one of the reasons why Greece produced some of the greatest thinkers the world has ever known?
Inessa [10]
The correct answer is C:
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6 0
3 years ago
A straight wire of length 0.62 m carries a conventional current of 0.7 amperes. What is the magnitude of the magnetic field made
anyanavicka [17]

Answer:

Magnetic field at point having a distance of 2 cm from wire is 6.99 x 10⁻⁶ T

Explanation:

Magnetic field due to finite straight wire at a point perpendicular to the wire is given by the relation :

B=\frac{\mu_{0}I }{2\pi R }\times\frac{L}{\sqrt{L^{2}+R^{2}  } }      ......(1)

Here I is current in the wire, L is the length of the wire, R is the distance of the point from the wire and μ₀ is vacuum permeability constant.

In this problem,

Current, I = 0.7 A

Length of wire, L = 0.62 m

Distance of point from wire, R = 2 cm = 2 x 10⁻² m = 0.02 m

Vacuum permeability, μ₀ = 4π x 10⁻⁷ H/m

Substitute these values in equation (1).

B=\frac{4\pi\times10^{-7}\times  0.7 }{2\pi \times0.02 }\times\frac{0.62}{\sqrt{(0.62)^{2}+(0.02) ^{2}  } }

B = 6.99 x 10⁻⁶ T

3 0
3 years ago
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