Answer:
Between a 12 gauge and a 22 gauge wire: the 12 gauge wire
Explanation:
Since the resistance in a wire is given by:
If both wires are made out of copper, the resistivity 
is the same.
The difference will remain in the cross area. The one with less area is the one with the greatest resistance.
Between the 2 gauge wires (22 and 12), the 12 gauge wire, with a diameter of 2.05mm is the one with smallest resistance.
The problem can be solve using the formula:
q = m Cp T
where q is the heat added to the substance
m is the mass of the substance
Cp is the specific of the substance
T is the change in temperature of the subtance
q = m Cp T
515 = m ( 4.18 ) ( 20)
m = 515 / ( 4.18) ( 20 )
m = 6.16 g of water
F(in) x d(in)= F(out)x d(out)
A machine has a mechanical advantage of 5.
F(out )= 5xF(in)300 newtons
F(in) = 300 N
F(out)= 5xF(in) = 5x300 N
= 1500 N
Work in = Work out = 3000 N x m3000
N x m = F_in x d_ind_in = 3000 Nxm / F_in = 3000 N x m / 300 N = 10 m3000 Nxm = F_out x d_out d_out = 3000 Nx m / F_out = 3000 N x m / 1500 N = 2 m
Answer:
D
Explanation:
I would say much too small as there is a significant portion of the plant that is UNDER water.....
( Really depends on how deep the water is...if it is shallow water it would be just a little too small)
