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Lelu [443]
3 years ago
11

A regulatory sign may be used to

Physics
1 answer:
charle [14.2K]3 years ago
4 0

Answer:

a. give limitations for using a particular lane of traffic

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Magnetic field lines exit out of the . Magnetic field lines enter into the . Magnetic field lines travel around a bar magnet in
Airida [17]

Answer:

Magnetic field lines exit out of the North pole . Magnetic field lines enter into the South pole. Magnetic field lines travel around a bar magnet in closed loops.

Explanation:

Magnetic field lines shows the direction of a magnetic force and how it acts, it gives the direction of the magnetic field at that point in time.

For a bar magnetic, the magnetic field lines runs from the north pole to the south pole, i.e. it exits the north pole and enters into the south pole. This magnetic field lines also go through the magnet forming closed loops without ends.

3 0
4 years ago
Read 2 more answers
The Moon requires about 1 month (0.08 year) to orbit Earth. Its distance from us is about 400,000 km (0.0027 AU). Use Kepler’s t
dem82 [27]

Answer:

\frac{M_e}{M_s} = 3.07 \times 10^{-6}

Explanation:

As per Kepler's III law we know that time period of revolution of satellite or planet is given by the formula

T = 2\pi \sqrt{\frac{r^3}{GM}}

now for the time period of moon around the earth we can say

T_1 = 2\pi\sqrt{\frac{r_1^3}{GM_e}}

here we know that

T_1 = 0.08 year

r_1 = 0.0027 AU

M_e = mass of earth

Now if the same formula is used for revolution of Earth around the sun

T_2 = 2\pi\sqrt{\frac{r_2^3}{GM_s}}

here we know that

r_2 = 1 AU

T_2 = 1 year

M_s = mass of Sun

now we have

\frac{T_2}{T_1} = \sqrt{\frac{r_2^3 M_e}{r_1^3 M_s}}

\frac{1}{0.08} = \sqrt{\frac{1 M_e}{(0.0027)^3M_s}}

12.5 = \sqrt{(5.08 \times 10^7)\frac{M_e}{M_s}}

\frac{M_e}{M_s} = 3.07 \times 10^{-6}

4 0
3 years ago
If 478 watts of power are used in 14 seconds,how much work was done
zepelin [54]

Answer:

6692J

Explanation:

Power is defined as the rate at which work is being done.

So,

    Power  = \frac{workdone}{time }  

  Work done  = Power x time

Given parameters:

Power  = 478watts

Time  = 14s

So;

 Work done  = 478 x 14  = 6692J

6 0
3 years ago
An example of a Destructive force is the formation of mountains True or False?
nata0808 [166]
Hey there!

<span>An example of a Destructive force is the formation of mountains.

This statement is false, an example of a destructive force would not be the formation of mountains.

Hope this helps you.
Have a great day!
</span>
3 0
3 years ago
Read 2 more answers
. Inside a laser apparatus, the stimulation and relaxation of electrons in atoms causes many photons with the same to be continu
mrs_skeptik [129]

Inside a laser apparatus, the stimulation and relaxation of electrons in atoms cause many photons with the same <u>wavelength </u>to be continuously emitted.

From the questions given, the main objective is to fill in the gaps and add important information where necessary. The missing information is highlighted in bold and underlined.

  1. Inside a laser apparatus, the stimulation and relaxation of electrons in atoms cause many photons with the same <u>wavelength </u>to be continuously emitted.

    2. When these photons are emitted, they travel between two <u>reflective </u>

         surfaces to form the wave that is represented in the simulation.

    3. This wave is the summation of all the photons being introduced with

        every oscillation, and as they continue to travel, the amplitude

        <u>increases. </u>

     4.  This occurs because the photons are emitted in a coherent fashion;

        however, amplitude when the photons overlap in an incoherent

        fashion.

     5.  In a laser device, a small portion of photons are permitted to escape

          (for use in an application). This is emulated in the simulation, by

         settling the Damping to Lots such that amplitude <u>remains relatively </u>

         <u>constant </u>when compared to damping of None. (Damping

         represents the Loss of photons.

       6. The generation of multiple wavelengths is possible in some laser

           producing systems, and the diffraction angle can be <u>varied</u> to allow

          the isolation of different wavelengths.

       7. Finally, when the power of a laser is described, the wave property

          that is being referenced is a function of its frequency and

          <u>amplitude.</u>

Therefore, we can conclude that we've fully understood the concept of emission of photons and wavelength in a laser apparatus.

Learn more about wavelength here:

brainly.com/question/23023103?referrer=searchResults

5 0
3 years ago
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