Answer:
C4H3O
Explanation:
Data obtained from the question include:
Carbon (C) = 68.85%
Hydrogen (H) = 4.95%
Since the vaccine contains carbon, hydrogen and oxygen, the remaining percentage will be for oxygen. The percentage of oxygen will be:
Oxygen (O) = 100 - (68.85 + 4.95)
= 26.2%
The empirical formula for the vaccine can be obtained as follow:
Carbon (C) = 68.85%
Hydrogen (H) = 4.95%
Oxygen (O) = 26.2%
Divide the above by their individual molar mass as shown below:
C = 68.85/12 = 5.7375
H = 4.95/1 = 4.95
O = 26.2/16 = 1.6375
Next, divide by the smallest number as shown below:
C = 5.7375/1.6375 = 4
H = 4.95/1.6375 = 3
O = 1.6375/1.6375 = 1
Therefore, the empirical formula for the vaccine is C4H3O
Because these characteristics do not depend on the amount of sample, nor do they change according to conditions.
Answer:
A. higher, lower
Explanation:
- Stronger intermolecular bonds require more energy and therefore create higher boiling points.
- Stonger intermolecular bonds create stronger interactions,which causes the vapor pressure to lower.
- Hope that helped! Please let me know if you need further explanation.
Answer:
I think this may help
Explanation:
Sum of subscripts on left = 92. Sum of subscripts on right = 57. So X must have atomic number = 92 – 57 = 35. Element 35 is bromine.
The chemical property of mercury is that it reacts with oxygen
