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nydimaria [60]
3 years ago
14

Three consecutive even numbers have a sum between 84 and 96. Write an inequality to find the three numbers. Let n represent the

smallest even number. Solve the inequality
Mathematics
2 answers:
yawa3891 [41]3 years ago
8 0

Answer:

28 30 and 32

Step-by-step explanation:

pantera1 [17]3 years ago
5 0
The numbers are: n, (n+2) and (n+4);
we can suggest this inequation:
84<n+(n+2)+(n+4)<96

Now, we solve this inequation:
84<n+(n+2)+(n+4)<96
84<3n+6<96

1)
3n+6>84
3n+6-6>84-6
3n>78
3n/3>78/3
n>26

2)
3n+6<96
3n+6-6<96-6
3n<90
3n/3<90/3
n<30

The solution is:
26<n<30

Then: n=28

The numbers will be: 28,30 and 32.

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zhenek [66]

The value of x in the proportion is x = 39/8

<h3>How to solve the proportion?</h3>

The proportion is given as:

3/8 =x/13

Cross multiply

8 * x = 3 * 13

Evaluate

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Divide by 8

x = 39/8

Hence, the value of x in the proportion is x = 39/8

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2 years ago
Susan has 343 cookies. She packs as many of them as she can equally in 19 boxes. She gives the rest to Mike. How many cookies do
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Answer:

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Step-by-step explanation:

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2 years ago
Which equation cab be used to solve for x in the triangle below ?
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Answer:

AA

Step-by-step explanation:

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3 years ago
Enter the product. Use expanded form to help.<br> 5 X 64<br> =
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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A disease has a constant force of mortality, µ. Historically 10% of all people with the disease die within 20 years. A more viru
kolbaska11 [484]

Answer:

Step-by-step explanation:

For the disease having force of mortality  µ.

we apply exponential distribution law

probability of dying within 20 years

p( x <20) = 1-e^{-\mu} = .1

e^{-\mu} = .9

For the disease having force of mortality  2µ.

we apply exponential distribution law

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p( x <20) = 1 - e^{-2\mu}

= 1 - ( .9)²

= 1 - .81

= .19

or 19%

5 0
3 years ago
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