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Alex73 [517]
3 years ago
7

A tennis ball is tossed upward with a speed of 3.0 m/s. We can ignore air resistance. What is the velocity of the ball .40 secon

ds after the toss?
Physics
2 answers:
alexira [117]3 years ago
6 0

Answer:

<em>Hello, The velocity of the ball is 0.92 m/s in the downward direction (-0.92 m/s).</em>

Explanation:

The equation for the velocity of an object thrown upward is the following:

v = v0 + g · t

Where:

v = velocity of the ball.

v0 = initial velocity.

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).

t = time.

To find the velocity of the ball at t = 0.40 s, we have to replace "t" by 0.40 s in the equation:

v = v0 + g · t

v = 3.0 m/s - 9.8 m/s² · 0.40 s

v = -0.92 m/s

The velocity of the ball is 0.92 m/s in the downward direction (-0.92 m/s).

<em>Hope That Helps!</em>

aksik [14]3 years ago
4 0

Answer:

It’s actually -0.92

Explanation:

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6 0
3 years ago
Question 2
yarga [219]

Answer:

24.4 m

Explanation:

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time = sqrt ( 2 * height / g)

time = sqrt (2 * 4 / 9.81)

time = 0,903 s

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8 0
3 years ago
Two positive charge spheres, the spheres are separated by 0.40 m. The charge on the first sphere is 100 microcoulombs and the
agasfer [191]

Answer: 168.75 N

Explanation:

first, let's convert microcoulombs to coulombs

q1 = 1e-4 C

q2 = 3e-5 C

r = 0.4 m

then use the equation Fe = \frac{kq_{1} q_{2}}{r^{2} }

plug in values --> F = (9e9*1e-4*3e-5)/(0.4)^2

F = 168.75 N

8 0
1 year ago
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