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Mars2501 [29]
2 years ago
12

What is the meaning of refraction in your own words?

Physics
1 answer:
Mice21 [21]2 years ago
4 0

Answer:

The fact of light and radio waves being deflected by passing obliquely through an interface between one medium or another.

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Calculate the change in internal energy (ΔE) for a system that is giving off 25.0 kJ of heat and is changing from 12.00 L to 6.0
Alexxandr [17]

Explanation:

The given data is as follows.

         q = -25.0 kJ,     Pressure (P) = 1.50 atm

   \Delta V = (12 - 6) L = 6 L

Therefore, product of pressure and change in volume will be as follows.

             P \Delta V = 1.50 atm \times 6 L

                                = 7.5 L atm

                                = 7.5 \times 101.3

                                = 759.75 J

Now, we will calculate the change in internal energy as follows.

                   \Delta E = q + w

                                = q + P \Delta V

                                = -25000 kJ + 759.75 J

                                 = 24240.25 J

or,                              = 24.240 kJ      (as 1 kJ = 1000 J)

Thus, we can conclude that the change in internal energy (\Delta E) for a system is 24.240 kJ.

7 0
4 years ago
Help me yall it due in a few minutes :((()
vaieri [72.5K]

Answer:

B. blocks 2 & 3.

Explanation:

Block 1 has equal & opposite forces acting on it.

Block 2 has 5N on one side, 3N on the other. It will move in the direction the 5N of force is pushing.

Block 3 has no opposing force.

6 0
3 years ago
A proton is accelerated from rest through a potential difference V0 and gains a speed v0. If it were accelerated instead through
Svet_ta [14]

Answer:

The speed is \sqrt{2}v_{0}.

(a) is correct option.

Explanation:

Given that,

Potential difference V= V_{0}

Speed v = v_{o}

If it were accelerated instead

Potential difference V'=2V_{0}

We need to calculate the speed

Using formula of initial work done on proton

W = q V

We know that,

\Delta W=\Delta K.E

q V=\dfrac{1}{2}mv^2

Put the value into the formula

q V_{0}=\dfrac{1}{2}mv_{0}^2

v_{0}^2=\dfrac{2qV_{0}}{m}....(I)

If it were accelerated instead through a potential difference of 2 V_{0}, then it would gain a speed will be given as :

Using an above formula,

v_{0}'^2=\dfrac{2qV_{0}}{m}

Put the value of V_{0}

v_{0}'^2=\dfrac{2q\times2V_{0}}{m}

v_{0}'=\sqrt{\dfrac{4qV_{0}}{m}}

v_{0}'=\sqrt{2}v_{0}

Hence, The speed is \sqrt{2}v_{0}.

6 0
3 years ago
The force required to start an object sliding across a uniform horizontal surface is larger than the force required to keep the
taurus [48]

The force required to start an object sliding across a uniform horizontal surface is larger than the force required to keep the object sliding at a constant velocity once it starts.

The magnitudes of the required forces are different in these situations because the force of kinetic friction is less than the force of static friction. <em>(d)</em>

3 0
3 years ago
Which number should be placed in the blank to make the equation balance? 3 H2+ N2 --- ______ NH3
miv72 [106K]
2 should be placed in the blank to make the equation balance. Btw, that's chemistry and not physics. Get it right.
7 0
3 years ago
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