I am sure the correct answer is B. Bonds are formed in order to make substances more stable than their former. Every process in this world works in order to achieve equilibrium or to be in a stable state this includes chemical reactions. Unstable substances will always find a way to become stable because it is the state with minimum energy.
Found it http://my.ccsd.net/userdocs/documents/uGKpi9UAEwFpSIgE.pdf
If it takes 35.04ml of a 0.2455M NaOH solution to neutralize 25. 00ml of an unknown HCl solution, the molarity of the HCl solution is 0.34M.
<h3>How to calculate molarity?</h3>
The molarity of a solution can be calculated using the following formula:
C1V1 = C2V2
Where;
- C1 = molarity of acid
- C2 = molarity of base
- V1 = volume of acid
- V2 = volume of base
According to this question, it takes 35. 04ml of a 0. 2455M NaOH solution to neutralize 25.00ml of an unknown HCl solution. The molarity of the HCl can be calculated as follows:
35.04 × 0.2455 = 25.0 × V2
8.602 = 25C2
C2 = 8.6/25
C2 = 0.34M
As a result, the molarity of the HCl solution is 0.34M if it takes 35. 04ml of a 0.2455M NaOH solution to neutralize 25ml of an unknown HCl solution.
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The answer is "filtration"
Filtration is used to separate solids from liquids or liquids from gases by adding a medium through which only the liquid can pass. The fluid that passes through is called filtrate.
I hope this helps.
Taking into account the reaction stoichiometry, 2.405 moles of NaCl are formed when 127.49 grams of Na₂CO₂ reacts with excess of FeCl₃.
<h3>Reaction stoichiometry</h3>
In first place, the balanced reaction is:
2 FeCl+ 3 Na₂CO₂ → Fe₂(CO₃)₃ + 6 NaCl
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- FeCl: 2 moles
- Na₂CO₂: 3 moles
- Fe₂(CO₃)₃: 1 mole
- NaCl: 6 moles
The molar mass of the compounds is:
- FeCl: 91.3 g/mole
- Na₂CO₂: 106 g/mole
- Fe₂(CO₃)₃: 291.7 g/mole
- NaCl: 58.45 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- FeCl: 2 moles ×91.3 g/mole= 182.6 grams
- Na₂CO₂: 3 moles ×106 g/mole= 318 grams
- Fe₂(CO₃)₃: 1 mole ×291.7 g/mole= 291.7 grams
- NaCl: 6 moles ×58.45 g/mole= 350.7 grams
<h3>Mass of NaCl produced</h3>
The following rule of three can be applied: if by reaction stoichiometry 318 grams of Na₂CO₂ form 6 moles of NaCl, 127.49 grams of Na₂CO₂ form how many moles of NaCl?
<u><em>moles of NaCl= 2.405 moles</em></u>
Then, 2.405 moles of NaCl are formed when 127.49 grams of Na₂CO₂ reacts with excess of FeCl₃.
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