The answer is the second choice (B)
EXPLANATION:
In a longitudinal wave the particle displacement is parallel to the direction of wave propagation. The animation at right shows a one-dimensional longitudinal plane wave propagating down a tube. The particles do not move down the tube with the wave; they simply oscillate back and forth about their individual equilibrium positions. Pick a single particle and watch its motion. The wave is seen as the motion of the compressed region (ie, it is a pressure wave), which moves from left to right.
The second animation at right shows the difference between the oscillatory motion of individual particles and the propagation of the wave through the medium. The animation also identifies the regions of compression and rarefaction.
Discuss the different observations that you would record during an investigation into the energy transformations of a lamp that uses electrical energy.
Answer:
Value of 
is 0.090.
Explanation:
Initial molarity of 
= 
= 0.0700 M
Construct an ICE table corresponding to the combustion reaction of carbon to determine
I (M): - 0.0700 0
C (M): - -x +2x
E (M): - 0.0700-x 2x
So, ![K_{c}=\frac{[CO]^{2}}{[O_{2}]}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5BCO%5D%5E%7B2%7D%7D%7B%5BO_%7B2%7D%5D%7D)
, where [CO] and ![[O_{2}]](https://tex.z-dn.net/?f=%5BO_%7B2%7D%5D)
represents equilibrium concentration of CO and respectively.
Here, ![[CO]=2x=0.060](https://tex.z-dn.net/?f=%5BCO%5D%3D2x%3D0.060)
⇒x = 0.030
So, = 0.0700-x = (0.0700-0.030) = 0.040
Hence, 
CH4 + 2O2→CO2 + 2H2O
Explanation:
CH4 + O2→CO2 + H2O
First look at the C atoms. At first glance they are balanced with 1 C on each side.
Now look at the H atoms. They are not balanced. There are 4 H atoms on the left side and 2 H atoms on the right. Place a coefficient of 2 in front of the H2O. We now have 4 H atoms on both sides.
CH4 + O2→CO2 + 2H2O
Now look at the O atoms. They are not balanced. There are 2 O atoms on the left side and 4 on the right. Place a coefficient of 2 in front of the O2. We now have 4 O atoms on both sides.
CH4 + 2O2→CO2 + 2H2O
The equation is now balanced. Each side has 1 C atom, 4 H atoms, and 4 O atoms.
Hey there!
Volume in mL :
1.68 L * 1000 => 1680 mL
Density = 0.921 g/mL
Therefore:
Mass = density * Volume
Mass = 0.921 * 1680
Mass = 1547.28 g
