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STALIN [3.7K]
3 years ago
6

Balancing carefully, three boys inch out onto a horizontal tree branch above a pond, each planning to dive in separately. The th

ird boy in line notices that the branch is barely strong enough to support them. He decides to jump straight up and land back on the branch to break it, spilling all three into the pond. When he starts to carry out his plan, at what precise moment does the branch break
Physics
1 answer:
VikaD [51]3 years ago
3 0

Answer:

what is this a riddle lol it breaks when he either jumps or lands

Explanation:

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Answer:

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Explanation:

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W = P d Cos 0°

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<u>FOR NORMAL FORCE (Fn) AND WEIGHT (W)</u>:

Since, normal force and weight are perpendicular to the motion of the box. Therefore, θ = 90°

Hence,

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W = Fn d(0) = mg d (0)

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<u>Therefore, work done by Normal Force (Fn) and Weight (mg) is Zero.</u>

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<u>FOR KINETIC FRICTIONAL FORCE (fk)</u>:

Since, kinetic frictional force acts in the opposite direction of motion of the box. Therefore, θ = 180°

Hence,

W = fk d Cos 180°

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W = -fk d

<u>Therefore, work done by Kinetic Frictional Force (fk) is Negative.</u>

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