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STALIN [3.7K]
3 years ago
6

Balancing carefully, three boys inch out onto a horizontal tree branch above a pond, each planning to dive in separately. The th

ird boy in line notices that the branch is barely strong enough to support them. He decides to jump straight up and land back on the branch to break it, spilling all three into the pond. When he starts to carry out his plan, at what precise moment does the branch break
Physics
1 answer:
VikaD [51]3 years ago
3 0

Answer:

what is this a riddle lol it breaks when he either jumps or lands

Explanation:

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A string under a tension of 68 N is used to whirl a rock in a horizontal circle of radius 3.7 m at a speed of 16.53 m/s. The str
alekssr [168]

Answer:

F = 5253.7 N

Explanation:

As we know that tension force in the string will be equal to the centripetal force on the string

so we will have

T = \frac{mv^2}{L}

now we have

68 = \frac{m(16.53^2)}{3.7}

now we have

68 = 73.8 m

m = 0.92 kg

now when string length is 0.896 m and its speed is 71.5 m/s then we will have

F = \frac{mv^2}{r}

F = \frac{0.92(71.5^2)}{0.896}

F = 5253.7 N

8 0
3 years ago
Read 2 more answers
How do Earth's and Jupiter's orbits compare?
shutvik [7]
Earth is smaller and have 1 moon so it rotates faster than jupiter and it have 6 moons
Also,earth is the earth is the earth and orbits the sun faster than jupiter the 7th

7 0
3 years ago
Help<br><br> Why does the sun move around the Milky Way galaxy
AnnyKZ [126]
It doesn't the sun stays still we move around the sun
5 0
3 years ago
Read 2 more answers
Julietta and Jackson are playing miniature golf. Julietta's ball rolls into a long. Straight upward incline with a speed of 2.95
Verdich [7]

Answer:

The length of the incline is 3.504 meters.

Explanation:

Let suppose that Julietta's ball decelerates uniformly, then we determine the length of the incline is determined by the following equation of motion:

\Delta s = v_{o}\cdot t +\frac{1}{2}\cdot a \cdot t^{2} (Eq. 1)

Where:

\Delta s - Length of the incline, measured in meters.

v_{o} - Initial speed of the ball, measured in meters per second.

a - Aceleration of the ball, measured in meters per square second.

t - Time, measured in second.

If we know that v_{o} = 2.95\,\frac{m}{s}, t = 1.54\,s and a = -0.876\,\frac{m}{s^{2}}, then the length of the incline is:

\Delta s = \left(2.95\,\frac{m}{s} \right)\cdot (1.54\,s)+\frac{1}{2}\cdot \left(-0.876\,\frac{m}{s^{2}} \right) \cdot (1.54\,s)^{2}

\Delta s = 3.504\,m

The length of the incline is 3.504 meters.

6 0
3 years ago
A copper wire has radius 0.800 mm and carries current I at 20.0°C. A silver wire with radius 0.500 mm carries the same current a
IgorC [24]

Answer:

Ecu/Eag = 0.46

Explanation:

E = PI/A

Ecu = Pcu × I/A

Pcu = 1.72×10^-8 ohm-meter

r = 0.8 mm = 0.8/1000 = 8×10^-4 m

A = πr^2 = π×(8×10^-4)^2 = 6.4×10^-7π

Ecu = 1.72×10^-8I/6.4×10^-7π = 0.026875I/1

Eag = Pag × I/A

Pag = 1.47×10^-8 ohm-meter

r = 0.5 mm = 0.5/1000 = 5×10^-4 m

A = πr^2 = π × (5×10^-4)^2 = 2.5×10^-7π

Eag = 1.47×10^-8I/2.5×10^-7π = 0.0588I/π

Ecu/Eag = 0.026875I/π × π/0.0588I = 0.46

7 0
3 years ago
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