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STALIN [3.7K]
3 years ago
6

Balancing carefully, three boys inch out onto a horizontal tree branch above a pond, each planning to dive in separately. The th

ird boy in line notices that the branch is barely strong enough to support them. He decides to jump straight up and land back on the branch to break it, spilling all three into the pond. When he starts to carry out his plan, at what precise moment does the branch break
Physics
1 answer:
VikaD [51]3 years ago
3 0

Answer:

what is this a riddle lol it breaks when he either jumps or lands

Explanation:

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Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The d
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a)Car E = Car D  > (Car F = Car B = Car C) > Car A

b)Car E = Car D  > (Car F = Car B = Car C) > Car A

Explanation:

Car A: mass = 500 kg; speed = 10 m/s

Car B: mass = 2000 kg;speed = 5 m/s

Car C:mass = 500 kg; speed = 20 m/s

Car D: mass = 1000 kg; speed = 20 m/s

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Part a) Now we know that momentum of each car is product of mass and velocity , so we will have

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P_1 = m \times v\\P_1 = (500)(10)\\P_1 = 5 \times 10^3 kg m/s

<em>Car B:</em>

P_2 = m v\\P_2 = (2000)(5)\\P_2 = 10^4 kg m/s

Car C:

P_3 = m v\\P_3 = (500)(20)\\P_3 = 10^4 kg m/s

Car D:

P_4 = m v\\P_4 = (1000)(20)\\P_4 = 2\times 10^4 kg m/s

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P_5 = m v\\P_5 = (4000)(5)\\P_5 = 2\times 10^4 kg m/s

Car F:

P_6 = m v\\P_6 = (1000)(10)\\P_6 = 10^4 kg m/s

So the momentum is given as ,

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so the order of impulse from largest to least is given as

Car E = Car D  > (Car F = Car B = Car C) > Car A

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