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STALIN [3.7K]
2 years ago
6

Balancing carefully, three boys inch out onto a horizontal tree branch above a pond, each planning to dive in separately. The th

ird boy in line notices that the branch is barely strong enough to support them. He decides to jump straight up and land back on the branch to break it, spilling all three into the pond. When he starts to carry out his plan, at what precise moment does the branch break
Physics
1 answer:
VikaD [51]2 years ago
3 0

Answer:

what is this a riddle lol it breaks when he either jumps or lands

Explanation:

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A 2.03 kg book is placed on a flat desk. Suppose the coefficient of static friction between the book and the desk is 0.602 and t
diamong [38]

Answer:

11.98 N

Explanation:

Normal force =   mg =  2.03 * 9.81

coeff of static friction must be overcome for the book to begin moving

       .602 = F / (2.03 * 9.81)   = 11.98  N

5 0
2 years ago
What is the correct definition of pH?
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Answer:

c

Explanation:

5 0
3 years ago
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You are a particle physicist at the Large Hadron Collider who is tasked with designing an apparatus to separate annihilation pro
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Find solution in the attachments

4 0
3 years ago
A huge tank of glycerine with a density of 1.260 g/cm3 is vertically stationed on a platform which is 15 m above the ground. The
EleoNora [17]

Answer:

The tank is losing 4.976*10^{-4}  m^3/s

v_g = 19.81 \ m/s

Explanation:

According to the Bernoulli’s equation:

P_1 + 1 \frac{1}{2} \rho v_1^2 + \rho gh_1 = P_2 +  \frac{1}{2}  \rho v_2^2 + \rho gh_2

We are being informed that both the tank and the hole is being exposed to air :

∴ P₁ = P₂

Also as the tank is voluminous ; we take the initial volume  v_1 ≅ 0 ;

then v_2 can be determined as:\sqrt{[2g (h_1- h_2)]

h₁ = 5 + 15 = 20 m;

h₂ = 15 m

v_2 = \sqrt{[2*9.81*(20 - 15)]

v_2 = \sqrt{[2*9.81*(5)]

v_2= 9.9 \ m/s  as it leaves the hole at the base.

radius r = d/2  = 4/2 = 2.0 mm

(a) From the law of continuity; its equation can be expressed as:

J = A_1v_2

J = πr²v_2    

J =\pi *(2*10^{-3})^{2}*9.9

J =1.244*10^{-4}  m^3/s

b)

How fast is the water from the hole moving just as it reaches the ground?

In order to determine that; we use the relation of the velocity from the equation of motion which says:

v² = u² + 2gh ₂

v² = 9.9² + 2×9.81×15

v² = 392.31

The velocity of how fast the water from the hole is moving just as it reaches the ground is : v_g = \sqrt{392.31}

v_g = 19.81 \ m/s

4 0
2 years ago
Suppose your local apparent solar time is 11 am, and you have a clock that says it is noon in Greenwich. What is your longitude
jeyben [28]

The longitude based on the time difference is 15 degrees.

<h3>Longitude of complete rotation of the Earth</h3>

The longitude of a complete rotation of the earth in a 24 hours is calculated  as follows;

= \frac{360^0}{24} = 15^0 \ of \ longitude

<h3>Time difference</h3>

The time difference between the local apparent solar time and the Greenwich time is calculated as follows;

t = 12 pm \ - \ 11 am\\\\t = 1 \ hour

Since it is one hour time difference, the longitude is 15 degrees.

Learn more about Earth longitude here: brainly.com/question/1939015

5 0
2 years ago
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