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babunello [35]
3 years ago
10

How many boxes of B would be required to make 30 grams of C?

Chemistry
1 answer:
Mashutka [201]3 years ago
3 0

Do you have a picture to go with it?

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A hot gas flowing through a pipeline can be considered as a:________
k0ka [10]

Answer:

B) irreversible process

Explanation:

The process given here is irreversible.

7 0
3 years ago
Gizmo Warm-up
Mariana [72]

Sodium hydroxide solution and hydrogen gas are produced from the reaction of water and sodium.

<h2>Reaction of sodium and water</h2>

We observe bubbles coming out of the water when the sodium reacts with the water because of the formation of hydrogen gas which is insoluble in water so it moves into the atmosphere.

<h3>Products of the reaction</h3>

Sodium metal reacts rapidly with water to form sodium hydroxide (NaOH) solution and hydrogen gas (H2). This chemical reaction is exothermic because huge amount of heat is release from the solution so we can conclude that sodium hydroxide solution and hydrogen gas are produced from the reaction of water and sodium.

Learn more about chemical reaction here: brainly.com/question/26018275

Learn more: brainly.com/question/26167984

8 0
2 years ago
This is the chemical formula for methyl acetate: CH32CO2. Calculate the mass percent of hydrogen in methyl acetate. Round your a
WITCHER [35]

<u>Answer:</u> The mass percent of hydrogen in methyl acetate is 8 %

<u>Explanation:</u>

The given chemical formula of methyl acetate is CH_3COOCH_3

To calculate the mass percentage of hydrogen in methyl acetate, we use the equation:

\text{Mass percent of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of methyl acetate}}\times 100

Mass of hydrogen = (6 × 1) = 6 g

Mass of methyl acetate = [(3 × 12) + (6 × 1) + (2 × 16)] = 74 g

Putting values in above equation, we get:

\text{Mass percent of hydrogen}=\frac{6g}{74g}\times 100=8.10\%=8\%

Hence, the mass percent of hydrogen in methyl acetate is 8 %

8 0
3 years ago
Calculate the amount of heat needed to boil of benzene (), beginning from a temperature of . Be sure your answer has a unit symb
Pavlova-9 [17]

Answer:

Check explanation

Explanation:

From the question, the parameters given are 64.7g of benzene,C6H6; a starting temperature of 41.9°C and bringing it to 33.2°C.

Molar mass of benzene,C6H6= 78.11236 g/mol.

Things to know: heat capacity of benzene, C6H6= 1.63 J/g.K, the heat of fusion = 9.87 kj/mol.

STEP ONE(1): ENERGY USED IN MELTING BENZENE SOLID.

Using the formula below;

Energy used in melting the solid(in JOULES) = (mass of benzene/molar mass of benzene) × heat of Fusion.

=(64.7 g of C6H6/ 78.11236(g per mol) of C6H6) × 9.87 kJ per mol.

= 8.175 J.

= 0.008175 kJ.

STEP TWO (2): ENERGY OF HEATING THE LIQUID.

It can be calculated from the formula below;

Energy= heat capacity (J/g.K) × mass of benzene× (∆T).

= 1.63 J/g.K × 64.7 × (41.9-33.2).

= 917.5J.

= 0.9175 kJ.

Energy required to boil benzene= Energy required to melt the bezene + energy required for boiling.

= 0.008175+ 0.9175.

= 0.93kJ

Approximately, 1 kJ

8 0
2 years ago
Fill in the blanks and correct anything that you think is wrong. Please?
kap26 [50]

you are right on all the ones you did

8 0
3 years ago
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