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3 years ago

6:

Mathematics

1 answer:

dem82 [27]3 years ago

3 0

Answer:

D) gallery: g

balcony: 2g

main floor: 2g + 225

Step-by-step explanation:

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What is the range of the function shown below<br> f(x)=-12/x^2+6

Musya8 [376]

Answer:

not sure i hope you find someone to help u tho soon

Step-by-step explanation:

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3 years ago

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55 divided (4 plus 7) times 6 plus(15 divided by3

Ne4ueva [31]

55/(4+7) x 6+(15/3)= 35

because...

55/(4+7)=5
5 x 6=30
30+(15/3)=35
So in total it equals to 35.

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The depth of a swimming pool is 8.5 meters. What half of the depth is in millimeters?

timofeeve [1]

4250 millimeters.
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3 years ago

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To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and find

loris [4]

Answer:

Option D - $[0.12$

Step-by-step explanation:

Given : The manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be s=0.16.

To find : The 95% confidence interval for the population standard deviation sigma?

Solution :

Number of sample n=19

The degree of freedom is Df=n-1=19-1=18

The standard deviation of the sample is s=0.16

Applying chi-square table to find critical value,

Upper critical value of $\chi^2$ is $UC=\chi(\frac{0.05}{2},18) = 31.5264$

Lower critical value of $\chi^2$ is

$LC=\chi(1-\frac{0.05}{2},18) = 8.2307$

Lower limit of the 95% confidence interval for the population variance

$L=\frac{(df)\times (s^2)}{UC}$

$L=\frac{18\times (0.16^2)}{31.5264}$

$L=\frac{18\times0.0256}{31.5264}$

$L=\frac{0.4608}{31.5264}$

$L=0.0146$

Upper limit of the 95% confidence interval for the population variance

$U=\frac{(df)\times(s^2)}{LC}$

$U=\frac{18\times (0.16^2)}{8.2307}$

$U=\frac{18\times0.0256}{8.2307}$

$U=\frac{0.4608}{8.2307}$

$U=0.0559$

So, The 95% confidence interval for the population variance is [0.0146, 0.0560]

Now, The 95% confidence interval for the population standard deviation is

$[\sqrt{0.0146}$

$[0.1208$

or $[0.12$

Therefore, Option D is correct.

The 95% confidence interval for the population standard deviation is $[0.12$

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2 years ago

HELP!!!!! What is the exclusion of 57x^5/19x^2??

Setler [38]

<span>57x^5/19x^2
= 3x^3

hope it helps</span>

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2 years ago