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Svetradugi [14.3K]
3 years ago
7

How do you feel when your out of breath ?

Physics
2 answers:
Aloiza [94]3 years ago
8 0
When you're out of breath, you feel dizzy, lung pain and maybe even nausea or side pain.
lisabon 2012 [21]3 years ago
3 0
Your heart beat real fast
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The lungs, nose, and trachea are organs of the respiratory system. Which best describes these organs?
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<span>They deliver oxygen to the blood. 

For the regular body activities to be carried out.

Acid-base balance or body temperature control.</span>
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3 years ago
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You have 2 objects flying towards you. One of them is havier with lower velocity and the other one is lighter but has higher vel
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Answer: I would say the object with the Lower velocity because Lighter with Higher velocity makes it heavy, velocity is how heavy something is so the lighter it is the less difficult it will be to catch.

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3 years ago
A simple model of a hydrogen atom is a positive point charge +e (representing the proton) at the center of a ring of radius a wi
Norma-Jean [14]

Answer:

Now e is due to the ring at a

So

We say

1/4πEo(ea/ a²+a²)^3/2

= 1/4πEo ea/2√2a³

So here E is faced towards the ring

Next is E due to a point at the centre

So

E² = 1/4πEo ( e/a²)

Finally we get the total

Et= E²-E

= e/4πEo(2√2-1/2√2)

So the direction here is away from the ring

8 0
3 years ago
Which of the following statements about Ohm's Law is true? A. Increasing the voltage decreases current. B. Keeping the same volt
Luden [163]

The correct answer is option D

The Ohm's Law states that current passing through a conductor is directly proportional to the voltage across the conductor.

Current =voltage/ resistance

The resistance causes hindrance in the path of the current and does not allows it to flow so, we must reduce the resistance to increase the flow of current in the conducting wire.





6 0
3 years ago
Read 2 more answers
Coulomb's law for the magnitude of the force FFF between two particles with charges QQQ and Q′Q′Q^\prime separated by a distance
SSSSS [86.1K]

Answer:

{F_{tot} = -1.092*10^{-2}N

Explanation:

The question: What is the net force exerted by these two charges on a third charge q_3 = 47.0 nC placed between q_1 and q_2 at x_3 = -1.240 mm ?

<u>Your answer may be positive or negative, depending on the direction of the force.</u>

Solution:

The coulomb force is given by the equation

F =k\dfrac{q_1 q_2}{d^2}.

where d is the separation between the charges q_1 and q_2.

Now, in our case

q_1=-13.5nC=-13.5*10^{-9}C

q_2=-1.735nC=-1.735*10^{-9}C

q_3= 47*10^{-9}C

The separation between charges q_3 and q_1 is

d_{31}= (-1.240mm)-(-1.735mm)=0.495mm=4.95*10^{-4} m

Therefore, the force between them is

F_{31} = (9*10^9NmC^{-2})\dfrac{47*10^{-9}*(-13.5*10^{-9})}{4.95*10^{-4}} =-0.01152N

and it is directed in the negative x-direction.

The separation between charges q_2  and q_3 is

d_{23} =-1.240mm-0=-1.240*10^{-3}m

therefore, the force between them is

F_{23} =(9*10^9Nm^2C^{-2})\dfrac{47*10^{-9}C*(-1.735*10^{-9}C)}{-1.240*10^{-3}m}=5.94*10^{-4}N

Therefore the total force on charge q_3 is

F_{tot} =5.94*10^{-4}-0.01152N = -0.010926N\\\\\boxed{F_{tot} = -1.092*10^{-2}N}

8 0
3 years ago
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