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3 years ago

What is one latitude where there is no continental barriers?

Physics

2 answers:

AveGali [126]3 years ago

5 0

The equator has no continental borders.

Arisa [49]3 years ago

3 0

Im pretty sure it is the <span>The equator.</span>

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A small block of mass 20.0 grams is moving to the right on a horizontal frictionless surface with a speed of 0.68 m/s. The block

Usimov [2.4K]

Answer:

a) $v'=-0.227\ m.s^{-1}$

b) $v=1.36\ m.s^{-1}$

Explanation:

Given:

mass of the lighter block, $m'=0.02\kg$

velocity of the lighter block, $u'=0.68\ m.s^{-1}$

mass of the heavier block, $m=0.04\ kg$

velocity of the heavier block, $u=0\ m.s^{-1}$

Using conservation of linear momentum:

$m'.u'+m.u=m'.v'+m.v$

where:

$v'=$ final velocity of the lighter block

$v=$ final velocity of the heavier block

$m'.u'=m'.v'+m.v$

$m'(u'-v')=m.v$ ........................(1)

Since kinetic energy is conserved in elastic collision:

$\frac{1}{2}m'.u'^2=\frac{1}{2}m'.v'^2+\frac{1}{2}m.v^2$

$m'(u'^2-v'^2)=m.v^2$

$m'(u'-v')(u'+v')= m.v^2$

divide the above equation by eq. (1)

$v=u'+v'$ .............................(2)

now we substitute the value of v from eq. (2) in eq. (1)

$m'(u'-v')=m(u'+v')$

$\frac{m'+m}{m'-m} =\frac{u'}{v'}$

$\frac{0.02+0.04}{0.02-0.04} =\frac{0.68}{v'}$

$v'=-0.227\ m.s^{-1}$ (negative sign denotes that the direction is towards left)

now we substitute the value of v' from eq. (2) in eq. (1)

$m'(u'-v+u')=m.v$

$2m'.u'=(m-m')v$

$2\times 0.02\times 0.68=(0.04-0.02)\times v$

$v=1.36\ m.s^{-1}$

6 0

3 years ago

Which bright object is in shadow

IRINA_888 [86]

My best guess would be sun because it is bright but is surrounded by shadows on all sides.

5 0

3 years ago

What is the term that describes waves that require a medium through which to travel?

gladu [14]

Answer:

Mechanical waves are waves that require a medium. This means that they have to have some sort of matter to travel through. These waves travel when molecules in the medium collide with each other passing on energy. One example of a mechanical wave is sound.

8 0

2 years ago

A particle moving in the x direction is being acted upon by a net force f(x)=cx2, for some constant

makkiz [27]

The work-energy theorem states that the change in kinetic energy of the particle is equal to the work done on the particle:
$\Delta K = W$
The work done on the particle is the integral of the force on dx:
$W= \int\limits^{3L}_L {F(x)} \, dx = \int\limits^{3L}_L {cx^2} \, dx = \frac{26}{3}cL^3$
So, this corresponds to the change in kinetic energy of the particle.

6 0

3 years ago

In a series rlc ac circuit, a second resistor is connected in parallel with the resistor previously in the circuit. as a result

raketka [301]

According to the given statement:

The frequency response does not change, which is the first thing we notice.

The new resistance at the resonance point causes a reduction in the circuit's current flow.
Z = R + R₂

<h3>The definition of series circuits:</h3>

electrical circuit. The path that the entire current takes as it passes through each component makes up a series circuit. Branching is used in parallel circuits to divide the current and limit the amount that flows through each branch.

<h3>How does a series circuit operate?</h3>

According to this definition, there are three principles of series circuits: all parts share the same current, resistances add up to a larger total resistance, and voltage drops add up to a larger total voltage. In the definition of a series circuit, all of these guidelines have their origin.

<h3>According to the given information:</h3>

The impedance of a series circuit is

Z₀² = R² + (X $_L$ -X $_C$ ) ²

The initial resistance impedance shifts to when we add another resistor to the series

Z² = (R + R₂) ² + (X $_L$ - X $_C$ ) ²

Let's examine this sentence.

The frequency response remains unchanged, which is the first thing we notice.
The new resistance at the resonance point causes the circuit's current to decrease.

Z = R + R₂

To know more about electrical circuit visit:

brainly.com/question/1922668

#SPJ4

6 0

1 year ago