Answer:
11.962337 × 10^-4 N
Explanation:
Given the following :
Length L = 11.8
Charge = 29nC = 29 × 10^-9 C
Linear charge density λ = 1.4 × 10^-7 C/m
Radius (r) = 2cm = 2/100 = 0.02 m
Using the relation:
E = 2kλ/r ; F =qE
F = 2kλq/L × ∫dr/r
F = 2*k*q*λ/L × (In(0.02 + L) - In(0.02))
2*k*q*λ/L = [2 × (9 * 10^9) * (29 * 10^9) * (1.4 * 10^-7)]/ 0.118] = 6193.2203 × 10^(9 - 9 - 7) = 6193.2203 × 10^-7 = 6.1932203 × 10^-4
In(0.02 + 0.118) - In(0.02) = In(0.138) - In(0.02) = 1.9315214
Hence,
(6.1932203 × 10^-4) × 1.9315214 = 11.962337 × 10^-4 N
First shell hold up to 2 electrons.
If you add 2 miles from west then 2 miles east then it would 4 miles all together.
Answer:
b. it has the same centripetal acceleration as car A.
Explanation:
According to the question, the data provided is as follows
Constant speed of car A = 20 m/s
Constant tangential acceleration until its speed is 40 m/s
Based on the above information, the true statement is the same centripetal acceleration as car A because
As we know that
Centripetal acceleration is

where,
= velocity
r = radius of the path
Now if both car A and car B moving in the same or identical circular path having the same velocity so in this case there is the same centripetal acceleration for that particular time
hence, the second option is correct
Answer:
<em>The grapefruit dropped 2.54 m and hit the ground at 7.06 m/s</em>
Explanation:
<u>Free Fall Motion
</u>
A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not encounter air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is 
The final velocity of a free-falling object after a time t is given by:
vf=g.t
The distance traveled by a dropped object is:

Given a grapefruit free falls from a tree and hits the ground t=0.72 s later, we can calculate the height it fell from:

y = 2.54 m
The final speed is computed below:

vf = 7.06 m/s
The grapefruit dropped 2.54 m and hit the ground at 7.06 m/s