10. A wheelbarrow is a second-class lever. Its wheel is the fulcrum, and its

True or false A ball thrown horizontally.Gravity causes the ball to continue horizontally.

sasho [114]

False is the correct answer.

6 0

4 years ago

On a frictionless track,cart 1 is moving with a constant,rightward(+) velocity of 1.0m/s.Cart 2 is also moving rightward with co

mamaluj [8]

Answer:

The final velocity of cart 1 is 3m/s

Explanation:

From principle of conservation of linear momentum, which states that sum of the momentum before collision is equal to the sum of the momentum after collision.

Momentum, P is given as mass x velocity.

ΔP = Δmv = m₁u₁ +m₂u₂ = m₁v₁ + m₂v₂

Assumptions:

If the two carts are moving on frictionless track, then limiting frictional forces due to their weights are negligible.

After the elastic collision, the two carts will move separately with different velocity

u₁ + u₂ = v₁ + v₂;

where;

u₁ and u₂ are the initial velocity for cart 1 and cart 2 respectively

v₁ and v₂ are the final velocity for cart 1 and cart 2 respectively

1 m/s + 5 m/s = v₁ + 3m/s

6 m/s = v₁ + 3m/s

v₁ = 6 m/s - 3m/s = 3m/s

Therefore, the final velocity of cart 1 is 3m/s

4 0

3 years ago

How is energy conserved in a transformation?

Aleksandr [31]

This depends entirely on the type of transformation of energy that is taking place, mechanical to thermal, thermal to mechanical, etc. But energy is always conserved, although it may take a different form.

4 0

3 years ago

Read 2 more answers

Two masses 1.2kg and 1.8kg are connected to the ends of a rod of length 2m. Find the moment of inertia about the axes, 1)going t

frutty [35]

Answers: 1) 3 kg m²

2) 2.88 kg m²

Explanation: Question 1

I = m(r)²+ M(r)²

I = 1.2 kg × (1 m )² +1.8 kg ×(1 m )²

∴ I = 3 kg m²

Question 2

ACCORDING TO THE DIAGRAM DRAWN FOR QUESTION 2

we have to decide where the center of gravity (G) lies and obviously it should lie somewhere near to the greater mass. (which is 1.8 kg). Since we don't know the distance from center of gravity(G) to the mass (1.8 kg) we'll take it as 'x' and solve!!

moments around 'G'

F₁ d ₁ = F₂ d ₂

12 (2-X) = 18 (X)

24 -12 X =18 X

∴ X = 0.8 m

∴ ( 2 - x ) = 1.2 m

∴ Moment of inertia (I) going through the center of mass of two masses,

⇒ I = m (r)² +M (r)²

⇒ I = 1.2 × (1.2)² + 1.8 × (0.8)²

⇒ I = 1.2 × 1.44 + 1.8 × 0.64

⇒ I = 1.728 + 1.152

⇒ ∴ I = 2.88 kg m²

∴ THE QUESTION IS SOLVED !!!

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8 0

3 years ago

3 m/s north is an example of a(n) ____.

alexandr1967 [171]

Rate of speed (3 m/s north is three miles per second north, so it's a rate of speed)

4 0

3 years ago

Read 2 more answers