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grin007 [14]
3 years ago
5

10. A wheelbarrow is a second-class lever. Its wheel is the fulcrum, and its

Physics
1 answer:
UNO [17]3 years ago
5 0
The answer that best suits this should be D
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True or false <br> A ball thrown horizontally.Gravity causes the ball to continue horizontally.
sasho [114]
False is the correct answer.
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4 years ago
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On a frictionless track,cart 1 is moving with a constant,rightward(+) velocity of 1.0m/s.Cart 2 is also moving rightward with co
mamaluj [8]

Answer:

The final velocity of cart 1 is 3m/s

Explanation:

From principle of conservation of linear momentum, which states that sum of the momentum before collision is equal to the sum of the momentum after collision.

Momentum, P is given as mass x velocity.

ΔP = Δmv = m₁u₁ +m₂u₂ = m₁v₁ + m₂v₂

Assumptions:

  • If the two carts are moving on frictionless track, then limiting frictional forces due to their weights are negligible.
  • After the elastic collision, the two carts will move separately with different velocity

u₁ + u₂ = v₁ + v₂;

where;

u₁ and u₂  are the initial velocity for cart 1 and cart 2 respectively

v₁ and v₂  are the final velocity for cart 1 and cart 2 respectively

1 m/s + 5 m/s = v₁  + 3m/s

6 m/s =  v₁  + 3m/s

v₁  = 6 m/s - 3m/s = 3m/s

Therefore, the final velocity of cart 1 is 3m/s

4 0
3 years ago
How is energy conserved in a transformation?
Aleksandr [31]
This depends entirely on the type of transformation of energy that is taking place, mechanical to thermal, thermal to mechanical, etc. But energy is always conserved, although it may take a different form.
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3 years ago
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Two masses 1.2kg and 1.8kg are connected to the ends of a rod of length 2m. Find the moment of inertia about the axes, 1)going t
frutty [35]

Answers: 1) 3 kg m²

                2) 2.88 kg m²

Explanation: <u> </u><u>Question 1</u>

                      I = m(r)²+ M(r)²

                      I = 1.2 kg × (1 m )² +1.8 kg ×(1 m )²

                    ∴  I =   3 kg m²

                       

                     <u> </u><u>Question 2 </u>

ACCORDING TO THE DIAGRAM DRAWN FOR QUESTION 2

we have to decide where the center of gravity (G) lies and obviously it should lie somewhere near to the greater mass.<em> (which is 1.8 kg). S</em>ince we don't know the distance from center of gravity(G) to the mass (1.8 kg) we'll take it as 'x' and solve!!

<u>moments around 'G' </u>

F₁ d ₁ = F₂ d ₂

12 (2-X) = 18 (X)

24 -12 X =18 X

∴  X = 0.8 m

∴ ( 2 - x ) = 1.2 m

∴ Moment of inertia (I) going through the center of mass of two masses,

⇒ I = m (r)² +M (r)²

⇒ I = 1.2 × (1.2)² + 1.8 × (0.8)²

⇒ I = 1.2 × 1.44 + 1.8 × 0.64

⇒ I = 1.728 + 1.152

⇒ ∴ I = 2.88 kg m²

∴ THE QUESTION IS SOLVED !!!

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8 0
3 years ago
3 m/s north is an example of a(n) ____.
alexandr1967 [171]
Rate of speed (3 m/s north is three miles per second north, so it's a rate of speed)
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3 years ago
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