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grin007 [14]
3 years ago
5

10. A wheelbarrow is a second-class lever. Its wheel is the fulcrum, and its

Physics
1 answer:
UNO [17]3 years ago
5 0
The answer that best suits this should be D
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A piano tuner is tuning a piano when he discovers that the G above middle C is vibrating with a higher frequency than his G tuni
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Tuning a piano is the process of adjusting the tension of its strings, thereby altering their pitch, or frequency of vibration, by slightly turning the tuning pins to which they're attached, so that each string sounds pleasingly in harmony with every other string.

<h2>Hopefully u will satisfy with my answer of ur question..!!</h2>

<h2>Have a nice day ahead dear..!!</h2>
6 0
3 years ago
In this circuit the resistance R1 is 7 Ω and R2 is 3 Ω. If this combination of resistors were to be replaced by a single resisto
Scilla [17]

Answer:

Series combination:

Equivalent resistance =10Ω

Parallel combination:

Equivalent resistance =\frac{21}{10} \Omega

Explanation:

Resistance: Resistance is the ratio of voltage to the current.

R=\frac{V}{I}

R = resistance

I = current

V= potential difference(voltage)

There are two types of resistance combinations.

  1. series combination
  2. parallel combination.

Series combination: If the ending point of one resistance is connected to the starting point of other resistance that combination is known as series combination.

If R₁,R₂ and R₃  are connected in series combination.

Then equivalent resistance = R₁+R₂+R₃

Parallel combination: If the ending point and the starting point of the all resistance are the same points that combination is known as parallel combination.

If R₁,R₂ and R₃  are connected in parallel combination.

Then equivalent resistance  \frac{1}{R}= \frac{1}{R_1}+ \frac{1}{R_2}+\frac{1}{R_3}

Here R₁=7Ω and     R₂=3Ω

If R₁ and R₂  connected in series combination

Then equivalent resistance = (7+3) Ω

                                            =10Ω

If R₁ and R₂  connected in parallel combination

Then equivalent resistance =\frac{1}{(\frac{1}{7} +\frac{1}{3})} \Omega

                                              =\frac{21}{10} \Omega

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