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grin007 [14]
3 years ago
5

10. A wheelbarrow is a second-class lever. Its wheel is the fulcrum, and its

Physics
1 answer:
UNO [17]3 years ago
5 0
The answer that best suits this should be D
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On February 15, 2013, Asteroid 2012 DA14 passed within 17,200 miles [mi] of the surface of the Earth at a relative speed of 7.8
xz_007 [3.2K]

Answer:

The total amount of energy that would have been released if the asteroid hit earth = The kinetic energy of the asteroid = 1.29 × 10¹⁵ J = 1.29 PetaJoules = 1.29 PJ

1 PJ = 10¹⁵ J

Explanation:

Kinetic energy = mv²/2

velocity of the asteroid is given as 7.8 km/s = 7800 m/s

To obtain the mass, we get it from the specific gravity and diameter information given.

Density = specific gravity × 1000 = 3 × 1000 = 3000 kg/m³

But density = mass/volume

So, mass = density × volume.

Taking the informed assumption that the asteroid is a sphere,

Volume = 4πr³/3

Diameter = 30 m, r = D/2 = 15 m

Volume = 4π(15)³/3 = 14137.2 m³

Mass of the asteroid = density × volume = 3000 × 14137.2 = 42411501 kg = 4.24 × 10⁷ kg

Kinetic energy of the asteroid = mv²/2 = (4.24 × 10⁷)(7800²)/2 = 1.29 × 10¹⁵ J

6 0
3 years ago
Acceleration always involves a change in
Scrat [10]
Velocity. Since velocity consists of a speed and a direction, acceleration is a change in speed, or direction, or both.
5 0
3 years ago
Which of the following is true about conduction? Question 2 options: It is heat transfer through direct contact It can only occu
kramer

Answer:

through direct contact

Explanation:

took the test!

3 0
3 years ago
IP The x and y components of a vector r⃗ are rx = 16 m and ry = -8.5 m , respectively
fiasKO [112]

as it is given that

r_x = 16 m

r_y = -8.5 m

now we will have

\vec r = 16 \hat i - 8.5 \hat j

now the magnitude of this vector is given as

|r| = \sqrt{16^2 + 8.5^2}

|r| = 18 m

now to find the direction we can use

tan\theta = \frac{r_y}{r_x}

tan\theta = \frac{-8.5}{16}

\theta = tan^{-1}(-0.53)

\theta = - 28^0

4 0
3 years ago
Show all your work clearly on the scratch paper) Two in-phase loudspeakers that emit sound with the same frequency are placed al
Darya [45]

Answer:

Explanation:

The speed of sound in air to be 343 m/s.

Given:

distance 'd' = 5 m

L = 12 m

It can be concluded that path difference must be equal to half of the wavelength when person is observing destructive interference'y' at 1 m distance from the equidistant position

Since

λ/2 = yd/L

λ/2 = (1 x 5)/12

λ = 0.833m

Frequency of the sound is given by,

f = v / λ => 343 / 0.833

f=411.6 Hz

8 0
3 years ago
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