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bagirrra123 [75]
3 years ago
9

if the angle btw the incline and horizontal surface is increased what will happen the magnitude of force needed to hold the obje

ct at rest on the incline

Physics
1 answer:
Scilla [17]3 years ago
6 0

Answer:

The force needed will be greater to hold the object at rest.

Explanation:

For a better understanding let's take a look at the attached image.

In the image there is an example of this condition, we have an object of 3 kg-f mass, the first angle between the horizontal and the inclined plane is 35°. When we increase the angle to 45°. We can realize that we need to hold the object with a stronger force.

The calculation and the equations based on Newton's laws can be found in the attached image.

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Two plane mirrors are separated by 120°, as the drawing illustrates. If a ray strikes mirror M1 at a θ1 = 64° angle of incidence
tino4ka555 [31]

Angle, θ2 at which the light leaves mirror 2 is 56°

<u>Explanation:</u>

Given-

θ1 = 64°

So, α will also be 64°

According to the figure:

α + β = 90°

So,

β = 90° - α

  = 90° - 64°

  = 26°

β + γ + 120° = 180°

γ = 180° - 120° - β

γ = 180° - 120° - 26°

γ = 34°

γ + δ = 90°

δ = 90° - γ

δ = 90° - 34°

δ = 56°

According to the law of reflection,

angle of incidence = angle of reflection

θ2 = δ = 56°

Therefore, angle θ2 at which the light leaves mirror 2 is 56°

8 0
3 years ago
a stone is vertically thrown upward with the velocity of 72km/hr find the maximum height reached the height​
dolphi86 [110]

Answer:

40m

Explanation:

v^2=gh

h=v^2/g

h=20^2/10

h=400/10

h=40

3 0
3 years ago
The momentum of a falling rock is found to be 200 kg m/s. What is the mass of the rock if it falls with a velocity of 5.0 m/s
Snezhnost [94]

Answer:

\boxed {\boxed {\sf 40 \ kilograms}}

Explanation:

Momentum is the product of velocity and mass. The formula is:

p=m*v

We know the rock is falling. Its momentum is 200 kilograms meters per second and its velocity is 5 meters per second. Substitute the values into the formula.

200 \ kg \ m/s = m * 5.0 \ m/s

We are solving for m, the mass. We must isolate the variable. It is being multiplied by 5 meters per second. The inverse of multiplication is division, so we divided both sides by 5.0 m/s.

\frac{200 \ kg \ m/s}{5.0 \ m/s}=\frac{ m* 5.0 \ m/s }{5.0 \ m/s}

\frac{200 \ kg \ m/s}{5.0 \ m/s}=m

The units of meters per second (m/s) cancel.

\frac{200 \ kg}{5.0 } =m

40 \ kg = m

The falling rock has a mass of <u>40 kilograms.</u>

4 0
3 years ago
A glider with mass m = 0.230 kg sits on a frictionless horizontal air track, connected to a spring with force constant k = 4.50
loris [4]

Answer

given,

mass of glider = 0.23 Kg

spring constant = k = 4.50 N/m

spring stretched to 0.130 m

The springs potential energy =

 U = \dfrac{1}{2}kx^2

 U = \dfrac{1}{2}\times 4.5 \times 0.13^2

        U = 0.038 J

at x = 0,the only energy will be kinetic .

 \dfrac{1}{2}mv^2=0.038

 \dfrac{1}{2}\times 0.23 \times v^2=0.038

         v² = 0.3304

         v = 0.575 m/s

displacement of the glider

      using conservation of energy

 \dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2

 x =v\sqrt{\dfrac{m}{k}}

 x =3\times \sqrt{\dfrac{0.23}{4.5}}

        x = 0.678 m

8 0
3 years ago
How do I remember the Mohs hardness scale?
yanalaym [24]
It's a hardness scale from 1-10 determining how easy or hard it is to scratch the mineral.

Remember that talc (like chalk or baby powder) is the softest and easiest to scratch then diamond being 10 is the hardest mineral to scratch or break or cut

6 0
3 years ago
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