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Arlecino [84]
3 years ago
14

The volume of a cone varies jointly with the base (area) and the height. The volume is 12.5 ft3 when the base (area) is 15 ft2 a

nd the height is 212 ft. Find the volume of the cone (after finding the variation constant) when the base (area) is 12 ft2 and the height is 6 ft
Mathematics
1 answer:
m_a_m_a [10]3 years ago
6 0

Answer:

the volume of the cone is V=0.283ft³

Step-by-step explanation:

From the question, we know that we are dealing with variation.

Then the variation can be interpreted as

V=kAh

Where K= constant of proportionality

Volume V= 12.5ft³

Height of cone h=212 ft.

Area of base of cone A= 15ft²

Then if we substitute into the expresion above, we have

12 .5= K × 15×212

K= 12.5/(15×212)

K=0.00393

Then when the base (area) is 12 ft² and the height is 6 ft

V=V=kAh

Substitute the new values we have

V= 0.00393× 12×6

V=0.283ft

Therefore, the volume of the cone is V=0.283ft³

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