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stich3 [128]
2 years ago
8

Please help ASAP please I’ll mark as brainlister

Mathematics
1 answer:
faust18 [17]2 years ago
7 0

Problems

The bottom of the red figure should be long; similar to the top of the blue figure.

The top of the red figure should be the same as the bottom of the blue figure.

Red are: (1, -1), (4, -1), (1, -5), (3, -5), (2, -2), (2, -4), (3, -4), (4, -2), (4, -2)

red points should be:

(1, -1), (3, -1), (1, -5), (4, -5),  (2, -2), (2, -4), (4, -4), (3, -2),  (3, -2),

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Step-by-step explanation:

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Answer: 0

Step-by-step explanation:

[24 - (15 + 2) +3] -9

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The age of some lecturers are 42,54,50,54,50,42,46,46,48 and 48 calculate the mean age and standard deviation
rjkz [21]

Answer:

Mean age: 48

Standard deviation: 4

Step-by-step explanation:

a) Mean

The formula for Mean = Sum of terms/ Number of terms

Number of terms

= 42 + 54 + 50 + 54 + 50 + 42 + 46 + 46 + 48+ 48/ 10

= 480/10

= 48

The mean age is 48

b) Standard deviation

The formula for Standard deviation =

√(x - Mean)²/n

Where n = number of terms

Standard deviation =

√[(42 - 48)² + (54 - 48)² + (50 - 48)² +(54 - 48)² + (50 - 48)² +(42 - 48)² + (46 - 48)² + (46 - 48)² + (48 - 48)² + (48 - 48)² / 10]

= √-6² + 6² + 2² + 6² + 2² + -6² + -2² + -2² + 0² + 0²/10

=√36 + 36 + 4 + 36 + 4 + 36 + 4 + 4 + 0 + 0/ 10

=√160/10

= √16

= 4

The standard deviation of the ages is 4

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