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Leno4ka [110]
3 years ago
7

Which of the following is not an example of a science? a.geology b.astrology c.astronomy d.ecology

Chemistry
1 answer:
Rasek [7]3 years ago
6 0
I think it is b.astrology

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Would you classify hydrogen as a metal or a non-metal? <br>Explain why.​
Igoryamba

Answer:

HYDROGEN IS A NON METAL.

HYDROGEN IS A GAS ELEMENT

Hydrogen is nonmetallic, except at extremely high pressures, and readily forms a single covalent bond with most nonmetallic elements, forming compounds such as water and nearly all organic compounds.

BRAINLIEST PLEASE, i really need it

5 0
2 years ago
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You need to make 10.0 L of 1.2 M KNO3. What molar ( concentration) would the potassium nitrate solution need to be if you were t
solniwko [45]

Answer:

2.5L [NaCl] concentrate needs to be 4.8 Molar solution before dilution to prep 10L of 1.2M KNO₃ solution.

Explanation:

Generally, moles of solute in solution before dilution must equal moles of solute after dilution.

By definition Molarity = moles solute/volume of solution in Liters

=> moles solute = Molarity x Volume (L)

Apply moles before dilution = moles after dilution ...

=> (Molarity X Volume)before dilution = (Molarity X Volume)after dilution

=> (M)(2.5L)before = (1.2M)(10.0L)after

=> Molarity of 2.5L concentrate = (1.2M)(10.0L)/(2.5L) = 4.8 Molar concentrate

6 0
3 years ago
Given a 1.50 Liters of solution that contains 62.5 grams of magnesium oxide. What is the Molarity of that solution? Please show
zhenek [66]
Given:
1.50 L
62.5 grams
and the MM of MgO: 40.31 g/mol

Molarity: mol/L

First, find mol.

62.5 g x 1mole ÷ 40.31 g = 1.55 mol

then divide mol and the given liters

1.55mol ÷ 1.50 L= 1.03 M
3 0
3 years ago
Which of the following have been determined as the oldest living tree types on Earth? Select all that apply.
fiasKO [112]
Sequoia and Bristle cone pine
6 0
3 years ago
At a given temperature, K = 1.3x10^-2 for the reaction:
son4ous [18]

Answer:

a) 0.11

b)76.9

c) 8.8

d) 1.7*10^-4

Explanation:

Step 1: Data given

K = 1.3 * 10^-2 for the reaction N2(g) + 3H2(g) ⇌ 2NH3(g)

Step 2: Formula of K

aA(g) + bB(g) ⇌ cC(g) + dD(g)

K = [C]^c *[D]^d  / [A]^a * [B]^b

K = 1.3 * 10^-2 = [NH3]² / [H2]³*[N2]

Step 3:

a) 1/2N2 + 3/2H2(g) ⇌ NH3(g)

N2(g) + 3H2(g) ⇌ 2NH3

1/2N2 + 3/2H2(g) ⇌ NH3(g)    =>K' =  \sqrt{K}

K' = \sqrt{1.3*10^-2} = 0.11

<em>b. 2NH3(g) ⇌ N2(g) + 3H2(g)</em>

N2(g) + 3H2(g) ⇌ 2NH3

2NH3(g) ⇌ N2(g) + 3H2(g)    =>K' = 1/K

K' = 1/(1.3*10^-2) = 76.9

c. NH3(g) ⇌ 1/2 N2(g) + 3/2H2(g)

N2(g) + 3H2(g) ⇌ 2NH3

NH3(g) ⇌ 1/2 N2(g) + 3/2H2(g)    

=>K' = \frac{1}{\sqrt{K} }

K' = \frac{1}{\sqrt{1.3*10^-2} }

K' = 8.8

d. 2N2(g) + 6H2(g) ⇌ 4NH3(g)

N2(g) + 3H2(g) ⇌ 2NH3

2N2(g) + 6H2(g) ⇌ 4NH3(g)

K' = K²

K' = (1.3*10^-2)²

K' = 1.7 *10 ^-4

4 0
3 years ago
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