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3 years ago

If lmn~ xyz which congruentes are true by CPCTC?

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

3 0

Answer:

Step-by-step explanation:

CPCTC: Corresponding Parts of Congruent Triangles are Congruent

If ΔLMN ≅ ΔXYZ, then:

B. LN ≅ XZ

C. ∠Y ≅ ∠M

E. MN ≅ YZ

<em>Corresponding sides:</em>

<em>Corresponding angles:</em>

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0/1<br> (-7x2 + 2x – 9) - (2 + 9x2 + 3x)<br> 7<br> 8<br> 9

loris [4]

The answer is 9 I believe

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3 years ago

Find the solutions of the form x=a,y=0and x=0 ,y=b for the following equations: 2x+5y=10 and 2x+3y=6. is there any common soluti

Arlecino [84]

Answer:

x=0 and y=2

Step-by-step explanation:

We have been given system of equations:

2x+5y=10 (1)

And 2x+3y=6 (2)

Subtract equation (2) from(1) we get:

2y=4

y=2

Now, substitute y=2 in equation(2) we get:

2x+3(2)=6

2x+6=6

2x=0

x=0

Hence, x=0 and y=2

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3 years ago

This table shows values represented by an exponential function.

Bad White [126]

Answer:

$a = 2 , f(2)=9$

$b = 4 , f(4)=64$

And replacing the data into the average rate formula we got:

$m = \frac{64-9}{4-2}= 27.5$

And then the best answer for this case would be:

C. 27.5

Step-by-step explanation:

For this cae we know that the average rate of change of a function is given by this general expresion:

$m = \frac{f(b) -f(a)}{b-a}$

For this special case from the info of the table we have:

$a = 2 , f(2)=9$

$b = 4 , f(4)=64$

And replacing the data into the average rate formula we got:

$m = \frac{64-9}{4-2}= 27.5$

And then the best answer for this case would be:

C. 27.5

7 0

3 years ago

The graph of y=x^3 is transformed as shown in the graph below. With. Equation represents the transformed function

taurus [48]

Answer: y' = (-x)^3 - 4

Step-by-step explanation:

The graph y = f(x) = x^3 passes trough the point (0,0)

because when x = 0

f(0) = y = 0^3 = 0

in the graph of the image, we can see that the graph intersects the y-axis in the point (0, -4)

This means that we have a vertical displacement of 4 units downwards.

When we have a graph y = f(x), a vertical translation of A units can be written as

y' = f(x) + A

If A is positive, the displacement is upwards, if A is negative, the displacement is downwards.

So if the displacement is of 4 units down, A = -4

We also have that when x is negative, the value of y is positive.

But in our original function, we have that for x = -1, y = (-1)^3 = -1

so in our original function, when x is negative also does y.

Then we also did a reflection around the y-axis, this means that we now evaluate the function in -x instead of x.

So the equation of the graph is:

y' = (-x)^3 - 4

8 0

3 years ago

For her presentation on the Wonders of the World, Mary baked a square pyramid-shaped cake as pictured below. The slant height of

mihalych1998 [28]

Answer:

$V=196in^3$

Step-by-step explanation:

The volume of a pyramid is:

$V=\frac{A_{b}h}{3}$

where $A_{b}$ is the area of the base and $h$ is the height (the perpendicular measurement between base and highest point, not the slant height)

Since the base is a square, the area is given by:

$A_{b}=l^2$

where $l$ is the length of the side: $l=8in$ , thus:

$A_{b}=(8in)^2\\A_{b}=64in^2$

Now we need to find the height, for this we use the right triangle that forms with half of a square side (8in/2 = 4in), the slant height (10in), and the height.

In this right triangle, the slant height is the hypotenuse, the leg 1 is the unknown height, and leg 2 is half of the square side.

Using pythagoras:

$hypotenuse^2=leg1^2+leg2^2$

substituting our values, and indicating that leg 1 is height h:

$(10in)^2=h^2+(4in)^2$

$100in^2=h^2+16in^2$

and solving for the height:

$h^2=100in^2-16in^2\\h^2=84in^2\\h=\sqrt{84in^2}\\ h=9.165in$

and finally we calculate the volume using this height and the area of the base:

$V=\frac{A_{b}h}{3}$

$V=\frac{(64in^2)(9.165in)}{3} \\V=195.5in^3$

rounding to the nearest cubic inch: $V=196in^3$

4 0

3 years ago