Question 2: Answer is (B), Soil Conservation Act (1936)
Hope that helps!!!
Answer:
(1) 0.0016 mol/L
Explanation:
Let the concentration of alcohol after 3.5 hours be y M
The reaction follows a first-order
Rate = ky^0 = change in concentration/time
k = 6.4×10^-5 mol/L.min
Initial concentration = 0.015 M
Concentration after 3.5 hours = y M
Time = 3.5 hours = 3.5×60 = 210 min
6.4×10^-5y^0 = 0.015-y/210
y^0 = 1
0.015-y = 6.4×10^-5 × 210
0.015-y = 0.01344
y = 0.015 - 0.01344 = 0.00156 = 0.0016 mol/L (to 4 decimal places)
Pressure has the opposite effect on air density increasing the pressure increases the density
Answer:
Option A. 6.75 (6.20/85.6)
Explanation:
The following data were obtained from the question:
Initial volume (V1) = 6.2cm³
Initial concentration (C1) = 6.75M
Final volume (V2) = 85.6cm³
Final concentration (C2) =.?
The final concentration can be obtained by using the dilution formula as show below:
C1V1 = C2V2
6.75 x 6.2 = C2 x 85.6
Divide both side by 85.6
C2 = (6.75 x 6.2) /85.6
C2 = 6.75 (6.2 / 85.6).