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qaws [65]
3 years ago
12

A pound is approximately 0.45 kilogram. A person weighs 87 kilograms. What is the person’s weight, in pounds, when expressed to

the correct number of significant figures?
A. 190 lb
B. 180 lb
C. 52 lb
D. 39 lb

Chemistry
2 answers:
Vinvika [58]3 years ago
6 0

Answer:

190 pounds  

Explanation:

Given that  

A pound is approximately 0.45 kilogram

A person weighs 87 kilograms

Now change the unit form kilogram to pounds as follows:

 

1 pound / 0.45 kilogram * 87 kilograms

= 193.3 pounds

Now expressed to the correct number of significant figures

193.3 pound = 190 pounds  

Sauron [17]3 years ago
4 0

Answer:

87 kilograms =191.8 pounds

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The three mass value measure are precise mass

<u>explanation</u>

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How many bromine are in 6NaBr?
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6 sodium and 6 Bromine in 6NaBr
5 0
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A compound contains nitrogen and a metal. This compound goes through a combustion reaction such that compound X is produced from
tia_tia [17]

Answer:

The correct answer is: X is nitrogen dioxide, and Y is a metal oxide

Explanation:

Combustion of compound of containing nitrogen and metal will give nitrogen  dioxide and metal oxide as product. During combustion reaction a compound reacts with oxygen in order to yield oxides of elements present in the compound.

The general equation is given as:

4M_3N_x+7xO_2\rightarrow 4xNO_2+6M_2O_x

Hence, the correct answer is :X is nitrogen dioxide, and Y is a metal oxide.

6 0
3 years ago
Ammonia, NH 3 , may react with oxygen to form nitrogen gas and water. 4 NH 3 ( aq ) + 3 O 2 ( g ) ⟶ 2 N 2 ( g ) + 6 H 2 O ( l )
Alex Ar [27]

Answer:

The limiting reactant is NH₃

0.0186moles of N₂ are the one produced by the limiting reactant

0.020 moles of N₂ are the one produced by the reactant in excess

Explanation:

This is the reaction

4NH₃ + 3O₂  → 2N₂ + 6H₂O

We should calculate the moles of each reactant

Mass / Molar mass = Moles

3.55 g / 17g/m = 0.208 moles NH₃

5.33 g / 32g/m = 0.166 moles O₂

4 moles of ammonia react with 3 moles of oxygen

0.208 moles of ammonia react with (0.208  .3)/4 = 0.156 moles O₂

We have 0.166 moles of O₂ and we need 0.156 moles, so O₂ is the reactant in excess.

3 moles of O₂ react with 4 moles of NH₃

0.166 moles of O₂ react with (0.166 . 4)/ 3 = 0.221 moles

We have 0.208 moles NH₃ and we need 0.221, so NH₃ is the limiting reactant.

To know the moles of N₂, let's apply the Ideal Gas Law

P.V =n.R.T

1atm . 0.450L = n . 0.082 . 295K

0.450 / (0.082 .295) = 0.0186 moles

If we have 100 % yield reaction:

4 moles NH₃ make 2 moles N₂

0.208 moles NH₃ make (0.208  .2)/4 = 0.104 moles

So the % yield reaction is.

0.104 moles ___ 100%

0.0186 moles ___ 17.9%

0.0186moles of N₂ are the one produced by the limiting reactant.

3 moles of O₂ produce 2 moles N₂

0.166 moles O₂ produce  (0.166  .2)/3 = 0.111 moles

Now, we apply the yield.

100% ____ 0.111 moles

17.9% = 0.020 moles

8 0
3 years ago
Read 2 more answers
Which of the following is not a conjugate acid-base pair?
-Dominant- [34]

Answer:

A. H3O+/OH−

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C. The conjugate pair of C₂H₃O₂⁻ is HC₂H₃O₂

D. The conjugate pair of H₂SO₃ is HSO₃⁻

That means right option, that is not a conjugate acid-base pair, is:

<h3>A. H3O+/OH− </h3>

5 0
3 years ago
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