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Bond [772]
3 years ago
13

A 5.0 gram sample of lead and a 3.2 g sample of iron are placed into 367 mL of water. What will be the new volume level of water

in units of mL? The density of lead is 11.34 g/cc and the density of iron is 7.874 g/cc.
Chemistry
1 answer:
olasank [31]3 years ago
3 0
Volume = mass/density 
Lead: v=5.0g/11.34g/cc = 0.440cc
For lead, the new volume level of water will be 367+0.440= 367.440ml

Iron: v=3.2g/7.874g/cc = 0.406cc
For Iron, the new volume level of water will be 367+0.406= 367.406ml 

If you add both, then it will be 367+0.406+0.440= 367.846 mL

First find the volume of each sample and then add that to 367ml of water. 

I hope that helps. 
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10 neutrons

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The graph shows the volume of a gaseous product formed during two trials of a reaction. A different concentration of reactant wa
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Write the symbol for each of the following ions:
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Answer:

a) _{31}^{71}\textrm {P^{3+}}

b) _{35}^{80}\textrm {Br^{-}}

c) _{90}^{232}\textrm {Th^{4+}}

d) _{38}^{87}\textrm {Sr^{2+}}

Explanation:

For neutral atoms:

Atomic Number (Z)= number of protons = number of electrons

Mass number (A) = number of protons + number of neutrons

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_{31}^{71}\textrm {P^{3+}}

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