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hodyreva [135]
3 years ago
14

Which is stronger ph4 or ph6

Chemistry
2 answers:
Temka [501]3 years ago
7 0

Answer:

ph4 is stronger

Explanation:

4 is the only moderate

5 - 6 are weak acids

0 - 3 are strong

Stels [109]3 years ago
3 0

ph4 is stronger because it is increasing acidity and ph6 is in the middle of neutral and increasing acidity
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which of the following is a physical change? 1.burning paper 2.grinding wheat 3.electrolysis of water 4.cooking rice​
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2 grinding of wheat is just a physical change

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2 years ago
What are some of thr similarties of physical changes and chemical changes?
Marysya12 [62]
The similarities of physical and chemical changes is that both of those changes change the way the object looks by it's physical appearance. Also they use a type of element to change that object.
5 0
3 years ago
Why can’t an atom lose or gain a proton
Veronika [31]

Explanation:

Atoms never gain protons; they become positively charge only by losing electrons. A positive ion is called a cation (pronounced: CAT-eye-on). You may have notice that the number of neutrons in each of these ions was not specified.

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3 years ago
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A balloon contains 2.0 L of air at 101.5 kPa . You squeeze the balloon to a volume of 0.25 L.
8_murik_8 [283]
<h3>Answer:</h3>

812 kPa

<h3>Explanation:</h3>
  • According to Boyle's law pressure and volume of a fixed mass are inversely proportional at constant absolute temperature.
  • Mathematically, P\alpha \frac{1}{V}

At varying pressure and volume;

P1V1=P2V2

In this case;

Initial volume, V1 = 2.0 L

Initial pressure, P1 = 101.5 kPa

Final volume, V1 = 0.25 L

We are required to determine the new pressure;

P2=\frac{P1V1}{V2}

Replacing the known variables with the values;

P2=\frac{(101.5)(2.0L)}{0.25L}

           = 812 kPa

Thus, the pressure of air inside the balloon after squeezing is 812 kPa

8 0
3 years ago
How many milliliters of a 1.5 m h2so4 are needed to neutralize 35ml sample of a 1.5 m solution?
DochEvi [55]

Answer:

1) 17.5 mL

Explanation:

Hello,

In this case, the reaction between sulfuric acid and potassium hydroxide is:

H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O

In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:

2*n_{acid}=n_{base}

And in terms of concentrations and volumes:

2*M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the volume of acid:

V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL

Best regards.

5 0
3 years ago
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