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Colt1911 [192]
3 years ago
15

For a particular isomer of C8H18, The following reaction produces 5093.7 KJ of heat per mole of C8H18(g) consumed under standere

d conditions. What is the standard enthalpy of formation of this isomer of C8H18(g)?
Chemistry
1 answer:
Aleks04 [339]3 years ago
7 0
02(g) = 0 kj/mol 
<span>CO2 (g) = -393.5 kj/mol </span>
<span>H20(g) = -241.8 kj/mol </span>

<span>H total = -5094 kJ
</span>5094kJ = [8(-393.5) + 9(-241.8)] - [X + 12.5(0)] 
<span>-5094 kJ = [-3148 + (-2176.2)] - [x + 0] </span>
<span>-5094 kJ = -5324.2 - x </span>

<span>add -5324.2 to -5094 </span>
<span>to get +230.2 = -x </span>

<span>move the negative to the other side </span>
<span>and you get -230 kj/mol</span>
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