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Morgarella [4.7K]
3 years ago
11

In a cold pack, which type of reaction draws heat from the surroundings?

Chemistry
1 answer:
Bingel [31]3 years ago
6 0
That would be an endothermic reaction! :)
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When does absorption occur in infrared spectroscopy
Vladimir79 [104]

Answer: hopefully this is right UwU

Explanation: The infrared spectrum of a sample is recorded by passing a beam of infrared light through the sample. When the frequency of the IR is the same as the vibrational frequency of a bond or collection of bonds, absorption occurs. Examination of the transmitted light reveals how much energy was absorbed at each frequency (or wavelength).

5 0
3 years ago
5Br−+BrO3−+6H+→3Br2+3H2O
sashaice [31]

Explanation :

The balanced chemical reaction is,

5Br^-+BrO_3^-+6H^+\rightarrow 3Br_2+3H_2O

The expression for the rates of consumption of the reactants are:

The rate of consumption of Br^- = -\frac{1}{5}\frac{d[Br^-]}{dt}

The rate of consumption of BrO_3^- = -\frac{d[BrO_3^-]}{dt}

The rate of consumption of H^+ = \frac{1}{6}\frac{d[H^+]}{dt}

The expression for the rates of formation of the products are:

The rate of consumption of Br_2 = +\frac{1}{3}\frac{d[Br_2]}{dt}

The rate of consumption of H_2O = +\frac{1}{3}\frac{d[H_2O]}{dt}

5 0
3 years ago
A _______ takes pictures and tracks the movements of clouds and air masses.
galina1969 [7]
A Weather Satellite. 
Hope this helps.

5 0
3 years ago
What is the mass of a neutron?<br><br> 1/2,000 amu<br> 1 amu<br> 2,000 amu<br> 1/200 amu
pashok25 [27]

Vas happenin!!



1 amu is the correct answer


Hope this helps


-Zayn Malik
8 0
3 years ago
Read 2 more answers
How many atoms of iodine are in 12.75g of CaI2? Hint. How many Iodines are there in one CaI2 particle?
xenn [34]

Answer:

5.225x10^{22}atoms\ I

Explanation:

Hello!

In this case, since 12.75 g of calcium iodide has the following number of moles (molar mass = 293.89 g/mol):

n_{CaI_2}=12.75gCaI_2*\frac{1molCaI_2}{293.89gCaI_2}=0.0434molCaI_2

In such a way, since 1 mole of calcium iodide contains 2 moles of atoms of iodine, and one mole of atoms of iodine contains 6.022x10²³ atoms (Avogadro's number), we compute the resulting atoms as shown below:

atoms\ I=0.0434molCaI_2*\frac{2molI}{1molCaI_2} *\frac{6.022x10^{23}atoms\ I}{1molI} \\\\atoms\ I = 5.225x10^{22}atoms\ I

Best regards!

4 0
3 years ago
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