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Whitepunk [10]
3 years ago
6

If sound becomes louder, which one of theses is increasing?

Physics
1 answer:
BaLLatris [955]3 years ago
7 0

Answer:

It will be increasing the Amplitude

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Which type of mine involves digging tunnels and shafts deep underground?
mel-nik [20]

The mine involves digging tunnels and shafts deep underground is the underground mining.

<h3>What is mining?</h3>

Mining is the digging of the Earth deep down in search of some precious elements or resources found on Earth.

Underground mining is the digging down into the earth in order to create tunnels. The shafts need to be inserted into those tunnels so that it reaches the deposits of resources.

Thus, underground mining involves digging tunnels and shafts deep underground.

Learn more about mining.

brainly.com/question/14277327

#SPJ4

7 0
1 year ago
The angle of deflection shows the amount of electric force on each balloon. A greater force causes the balloon to deflect to a g
UNO [17]

Answer:

Hello the options to your question is missing attached below are the missing options

  • Electrical forces are symmetrical, The electric repulsion of the Balloons is equal because electric forces between two objects are always symmetrical
  • The electric forces are equal in this case because both balloons had the same amount of electric charge

Answer :

Electrical forces are symmetrical, The electric repulsion of the Balloons is equal because electric forces between two objects are always symmetrical

Explanation:

The Balloons have the same amount of force exerted on them, because Electrical forces are symmetrical, The electric repulsion of the Balloons is equal because electric forces between two objects are always symmetrical, therefore the two Balloons are deflected to the same angle

7 0
3 years ago
A car is traveling at 39.7 mi/h on a horizontal highway. The acceleration of gravity is 9.8 m/s 2 . If the coefficient of fricti
777dan777 [17]

Answer:

The minimum distance in which the car will stop is

x=167.38m

Explanation:

39.7\frac{mi}{h}*\frac{1km}{0.621371mi}*\frac{1000m}{1km}*\frac{1h}{3600s}=17.747\frac{m}{s}

∑F=m*a

∑F=u*m*g

The force of friction is the same value but in different direction of the force moving the car so it can stop so

F=m*a\\a=\frac{F}{m}\\a=\frac{u*m*g}{m}\\a=u*g\\a=0.096*-9.8\frac{m}{s^{2} }

a=-0.9408 \frac{m}{s^{2}}

v_{f}^{2}=v_{o}^{2}+2*a*(x_{f}-x_{o})\\v_{f}=0 \\x_{o}=0\\0=v_{o}^{2}+2*a*x_{f}\\x_{f}=\frac{v_{o}^{2}}{2*a} \\x_{f}=\frac{(-17.747\frac{m}{s})^{2}}{2*(-0.9408)} \\x_{f}=167.38m

4 0
3 years ago
People who view society as a set of interrelated parts that work together to produce a stable social system are said to employ t
AURORKA [14]
The answer is d. functionalist perspective 
7 0
3 years ago
On a small planet, an astronaut uses a vertical
sleet_krkn [62]
Constant velocity means the netto force = 0, therefore F(gravity) = F(astronaut).
175N divided by 87,5kg = 2.00kg/N
6 0
2 years ago
Read 2 more answers
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