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Whitepunk [10]
3 years ago
6

If sound becomes louder, which one of theses is increasing?

Physics
1 answer:
BaLLatris [955]3 years ago
7 0

Answer:

It will be increasing the Amplitude

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How many shells does the element neon have?<br> A.1<br> B.2<br> C.8<br> D.18
ZanzabumX [31]
The answer should be B.

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3 years ago
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A force 1500 n to a 100 kg car . what is the acceleration of the car
dezoksy [38]
F = ma

F 1500N
m = 100 kg

1500 = 100 * a

Solve for a.
3 0
3 years ago
A mass m1= 6.20 kg is moving North with a velocity of v1= 13.5m/sec when it collides perpendicularly with another mass m2= 4.40
JulijaS [17]

Answer:

Momentum of mass m_{1} is 83·7 kg m/s towards north

Momentum of mass m_{2} is 38·72 kg m/s towards east

Explanation:

Given

Mass of m_{1} = 6·2 kg

Mass of m_{2} = 4·4 kg

Velocity of mass m_{1} = v_{1} = 13·5 m/s

Velocity of mass m_{2} = v_{2} = 8·8 m/s

Momentum of mass m_{1} = m_{1} × v_{1} = 6·2 × 13·5 = 83·7 kg m/s

Momentum of mass m_{2} = m_{2} × v_{2} = 4·4 × 8·8 = 38·72 kg m/s

As mass m_{1} is moving North, the direction of momentum will also be in that direction because the direction of momentum will be in the direction of velocity

As mass m_{2} is moving East, the direction of momentum will also be in that direction because the direction of momentum will be in the direction of velocity

∴ Momentum of mass m_{1} is 83·7 kg m/s towards north

∴ Momentum of mass m_{2} is 38·72 kg m/s towards east

7 0
3 years ago
What is the molarity (concentration) of 25.2 grams of NaF dissolved in a total volume of 0.75 liters?
vodka [1.7K]

Answer: concentration c = 25.2 g /(41.99 g/mol × 0.75 l)

Explanation: M(NaF) = 41.99 g/mol and amount of substance n = m/M.

Concentration c = n/V

6 0
3 years ago
the Latent heat of fusion of aluminum is 93 KCAL / kg at 660 degrees Celsius determine the amount of energy needed to melt 100 k
True [87]

Answer: 9300 kcal

Explanation: Given: Latent heat of fusion of aluminum is 93 kcal/kg.

That is for melting 1 kg of aluminium at 660^0C amount of heat required is = 93kcal

Thus for 100 kg of aluminium at 660^0C amount of heat required is= \frac{93}{1}\times 100=9300kcal

Thus the amount of energy needed to melt 100 kg of aluminum at the melting point is 9300 kcal.


8 0
3 years ago
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