Could someone please answer this question for me? Also pls provide a detailed explanation. Thanks in advance
1 answer:
Answer:
-0.4 m/s
Explanation:
We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the shell + cannon system must be conserved.
Before the shot, the total momentum of the system is zero:
p = 0
After the shot, the total momentum is:
where
m = 3.0 kg is the mass of the shell
v = 200 m/s is the velocity of the shell
M = 1500 kg is the mass of the cannon
V is the recoil velocity of the cannon
Since momentum is conserved, the initial and final momenta must be equal, therefore:
Where the negative sign indicates that the cannon moves in the opposite direction to the shell.
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Answer:
Where represent the force for each of the 5 cases
presented on the figure attached.
Explanation:
For this case the figure attached shows the illustration for the problem
We have an inverse square law with distance for the force, so then the force of gravity between Earth and the spaceship is lower when the spaceship is far away from Earth.
Th formula is given by:
Where G is a constant
represent the mass for the earth
represent the mass for the spaceship
represent the radius between the earth and the spaceship
For this reason when the distance between the Earth and the Spaceship increases the Force of gravity needs to decrease since are inversely proportional the force and the radius, and for the other case when the Earth and the spaceship are near then the radius decrease and the Force increase.
Based on this case we can create the following rank:
Where represent the force for each of the 5 cases
presented on the figure attached.
