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netineya [11]
3 years ago
11

PLS I NEED HELP with steps WILL GIVE BRAINLIEST

Chemistry
1 answer:
RideAnS [48]3 years ago
8 0

Answer:

Please subscribe to my channel Symbol YT then I will answer your question

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Is the distilled water/acidic/basic/netural?​
SVEN [57.7K]
Distilled water is neutral, because the H+ and OH- ions are balanced. Litmus is a natural acid-base indicator extracted from a type of lichen.
7 0
2 years ago
PLEASE HELP I WILL GIVE YOU 100 POINTS ON THE NEXT QUESTION
REY [17]

Answer:

okay so lets say i drop a ball that weighs 2 pounds off a building and a ball that ways 1 pound off the building at the same time the lighter ball would hit the ground first because its lighter and so they heavier it is the slower it drops the lighter it is the faster it drops

Explanation:

6 0
3 years ago
Assuming that a sample of ethanol weighs 560 grams. What is the mass of hydrogen in grams for the sample?
Novosadov [1.4K]

Answer:

BRO WHAT THEY ANSWER TO UR BUT NOT MINE OK

Explanation: I THINK THE ASNSWER IS C BUT NOT SURE.... HOPE IT HELPS

6 0
2 years ago
You could add aquous hydrochloric to the solution to precipitate out silver chloride. What volume of a 0.130 M aqueous hydrochlo
Mila [183]
1) Chemical reaction: AgNO₃ + HCl → AgCl + HNO₃.
V(AgNO₃) = 30,0 mL = 0,03 L.
c(AgNO₃) = 0,225 mol/L.
n(AgNO₃) = 0,03 L · 0,225 mol/L.
n(AgNO₃) = 0,00675 mol.
From chemical reaction: n(AgNO₃) : n(HCl) = 1 : 1.
0,00675 mol : n(HCl) = 1 : 1.
n(HCl) = 0,00675 mol.
V(HCl) = n(HCl) ÷ c(HCl).
V(HCl) = 0,00675 mol ÷ 0,130 mol/L.
V(HCl) = 0,0519 L = 51,92 ml.

2) 1) Chemical reaction: AgNO₃ + KCl → AgCl + KNO₃.
V(AgNO₃) = 30,0 mL = 0,03 L.
c(AgNO₃) = 0,225 mol/L.
n(AgNO₃) = 0,03 L · 0,225 mol/L.
n(AgNO₃) = 0,00675 mol.
From chemical reaction: n(AgNO₃) : n(KCl) = 1 : 1.
0,00675 mol : n(KCl) = 1 : 1.
n(KCl) = 0,00675 mol.
m(KCl) = n(KCl) · M(KCl).
m(KCl) = 0,00675 mol · 74,55 g/mol.
m(KCl) = 0,503 g.
n - amount of substance.
M - molar mass.
5 0
3 years ago
Number of representative particles in 3 moles Sn
AURORKA [14]

Answer:

18.066 × 10²³ particles

Explanation:

Given data:

Number of moles of Sn = 3 mol

Number of representative particles = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For 3 mole of Sn:

3 × 6.022 × 10²³ particles

18.066 × 10²³ particles

5 0
3 years ago
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