Question

To hoist himself into a tree, a 72.0-kg man ties one end of a nylon rope around his waist and throws the other end over a branch of the tree. He then pulls downward on the free end of the rope with a force of 358 N. Neglect any friction between the rope and the branch, and determine the man’s upward acceleration.

Answer 1

Answer:

acceleration a= 0.1344 m/sec^2

Explanation:

Given

mass of the object m= 72 kg

Force applied with help of rope= 358 N

Acceleration due to gravity= 9.81 m/sec^2

Since there is no force acting on the person and rope

then  T=F

and from the FBD we can write

2T- mg= ma ,or

2F- mg= ma

$a=\frac{2F-mg}{m}$

now putting the values we get

$a=\frac{2F-mg}{m}$

$a=\frac{2\times358-72\times9.81}{72}$

on calculating we get acceleration a= 0.1344 m/sec^2